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Oliga [24]
3 years ago
9

Two​ pulleys, one with radius 4 inches 4 inches and one with radius 8 inches 8 inches​, are connected by a belt. If the 4 dash i

nch4-inch pulley is caused to rotate at 5 revolutions per minute5 revolutions per minute​, determine the revolutions per minute of the 8 dash inch8-inch pulley. ​ (Hint: The linear speeds of the pulleys are the​ same, both equal the speed of the​ belt.)
Physics
1 answer:
amid [387]3 years ago
5 0

Answer:

n_2 = 2.5 rev/min

Explanation:

The pulleys are two wheels, one driving, which is where the motor is that makes it spin, and another driven thanks to the friction that occurs between them and a belt that joins them. It is evident, seeing this example, that the smallest wheel should turn faster than the largest.

In all pulleys the formula is met:

n_1 * D_1 = n_2* D_2

where "D1" and "D2" is the value of the diameter (or ratio)of each of the pulleys and "n1" and "n2" is the speed of rotation, that is, the number of revolutions per minute given by each pulley.

So

D_1 = 4in\\D_2 = 8in\\n_1 = 5rev/min\\n_2=?

Replacing,

(4)(5)=n_2(8)

clearing n_2

n_2 = \frac{4*5}{8}

n_2 = 2.5 rev/min

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We have three identical metallic spheres A, B, C. Initially sphere A is charged with charge Q, while B and C are neutral. First,
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Answer:

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Explanation:

This problem asks for the final charge of each sphere, for this we must use that the charge is distributed evenly over a metal surface.

Let's start Sphere A makes contact with sphere B, whereby each one ends with half of the initial charge, at this point

                q_A = Q / 2

                q_B = Q / 2

Now sphere A touches sphere C, ending with half the charge

                q_A = ½ (Q / 2) = ¼ Q

                q_B = ¼ Q

Now the sphere A that has Q / 4 of the initial charge is put in contact with the sphere B that has Q / 2 of the initial charge, the total charge is the sum of the charge

                  q = Q / 4 + Q / 2 = ¾ Q

This is the charge distributed between the two spheres, sphere A is 3/8 Q and sphere B is 3/8 Q

                  q_A = 3/8 Q

                  q_B = 3/8 Q

The final charges of each sphere are:

                q_A = 3/8 Q

                q_B = 3/8 Q

                q_C = 3/4 Q

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3 years ago
What if m1 is initially moving at 3.4 m/s while m2 is initially at rest? (a) find the maximum spring compression in this case?
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yKpoI14uk [10]

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2 years ago
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a spring with a constant of 80N/m is stretched by a force of 240N. how much the displacement of the spring from equilibrium?
Inessa05 [86]

Answer:

1200N/m

Explanation:

given parameters:

force on the motorcycle spring is 240N

Extension 2cm or 0.02m

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k=1200N/m

8 0
2 years ago
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