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LuckyWell [14K]
2 years ago
10

calculate the amount of work done by a person while taking a bag of mass 100kg to the top of the building hight 10m. The mass of

the person is10kg
Physics
1 answer:
vredina [299]2 years ago
6 0

Explanation:

Total mass=100+10=110

Total weight=mass×gravitational field strength

=110×10

=1100N

Work done=force×distance

=1100×10

=11000J

<em>Please mark me as brainliest if this helped you!</em>

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The answer is reflection.
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3 years ago
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Four seconds after being launched, what is the height of a ball that starts from a height of 12 m with an initial upward velocit
MrMuchimi

Answer:

15.24 m/s in the downward direction

Explanation:

Given that the initial upward velocity of the ball is 24 m/s.

Assuming that the upward direction is positive.

As gravitational force acts in the downward direction and the direction of acceleration is the same as the direction of force, so the acceleration due to gravity will be negative.

Now, from the equation of motion, when an object is launched with initial velocity u, the final velocity, v, of an object after time t is v=u+at.

Given that u=24 m/s, t=4 seconds, g=-9.81 m/s^2.

So, the final velocity is

v= 24 + (-9.81)\times 4 \\\\\Rightarrow v= 24-9.81\times 4

\Rightarrow v=-15.24 m/s

Here, the negative sign means the final velocity is in the downward direction.

Hence, the velocity after 4 seconds is 15.24 m/s in the downward direction.

8 0
3 years ago
How much force must be applied for a 150.W motor to keep a package moving at 3.00m/s?
leva [86]

The force must be applied for motor to keep the package moving is 50 N.

<h3>What is force?</h3>

Force is the action of push or pull the object in order to make it move or stop.

Power is related to force and velocity as

P = F x v

150 W = F x 3 m/s

F  =50 N

Thus, the force must be applied for motor to keep the package moving is 50 N.

Learn more about force.

brainly.com/question/13191643

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7 0
1 year ago
Three laws that indicate a chemical change
alexandr1967 [171]

Temperature, The highness, and the time.

Hope this helps!

C=

4 0
3 years ago
A truck on a straight road starts from rest, accelerating at 2.00m/s^2 until it reaches a speed of 20.0m/s. Then the truck trave
Dennis_Churaev [7]

Answer:

Explanation:

a )

Time to reach the speed of 20 m/s with an acceleration of 2 m/s² can be calculated as follows .

v = u + a t

20 = 0 + 2 t

t = 20 /2 = 10 s .

Total time = 10 s + 20 s + 5 s = 35 s .

b) Average velocity = Total distance travelled / total time

Distance travelled in first 10 s

S₁ = ut + 1/2 a t²

= 0 + .5 x 2 x 10²

= 100 m

Distance travelled in next 20 s

S₂= 20s x 20 m/s  = 400 m

Distance travelled in last 5 s .

deceleration in last 5 s

v = u + at

0 = 20 m/s + a x 5

a = - 4 m/s²

v² = u² - 2 a s

0 = (20 m/s)² - 2 x 4 m/s² x s

s = 50 m

S₃ = 50 m

Total distance = S₁ + S₂ + S₃

= 100 m + 400 m + 50 m

= 550 m .

Average velocity = 550 m / 35 s

= 15.71 m /s .

3 0
3 years ago
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