Answer:
a) the minimun of acetic anhydride required for the reaction is 2.175 g (CH3CO)2O
b) V acetic anhydride = 2.010 mL
Explanation:
C6H4OHCOOH + (CH3CO)2O ↔ C9H8O4 + C2H4O2
⇒ mol salicylic acid = 2.94 g C6H4OHCOOH * ( mol C6H4OHCOOH / 138.121 g ) = 0.0213 mol C6H4OHCOOH
⇒ mol acetic anhydride = 0.0213 mol C6H4OHCOOH * ( mol (CH3CO)2O / mol C6H4OHCOOH ) = 0.0213 mol (CHECO)2O
⇒ g acetic anhydride = 0.0213 mol * ( 102.1 g/mol ) = 2.175 g CH3CO)2O
b) V = 2.175 g (CH3CO)2 * ( mL / 1.082 g ) = 2.010 mL (CH3CO)2O
<span>These are the rules of the quantum numbers that you have to use to dilucidate the validity of a set of quantum numbers:
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<span>1) Main quantum number, n: 1, 2, 3, 4, 5, 6, 7
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2) Second quantum number, ℓ: 0, 1, 2, ... n-1
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<span>3) Third quantum number (magnetic quantum number), mℓ: -l,...0,,,,+l
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<span>4) Fourth quantum number (spin): ms: +1/2 or -1/2
</span>
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Answers:
<span>i) 3,2,0,1/2: valid, because 0<= l < n; - l <= ml <= +l; and ms = +1/2 or -1/2
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</span><span>ii) 2,2,-1, 1/2 invalid because l = n (violates second rule)</span><span /><span>
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</span><span>iii) 4,3,-4,1/2 invalid because ml is less than - l (violates third rule)</span><span /><span>
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</span><span>iv) 1,0,0,1/2 valid: meet the four rules</span><span /><span>
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</span><span>v) 2,2,1,-1/2 invalid because l = n (violate the second rule)</span><span /><span>
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</span><span>vi) 3,2,1,1 invalid because ms can be only +1/2 or -1/2 (fourth rule)
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<span /><span /><span>vii) 0,1,1,-1/2 invalid because l > n (violates rule 2)
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<span /><span /><span>viii) 3,3,1,1/2 invalid because l = n (violate rule 2)
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<span /><span /><span>ix) 2,-2,-2,-1/2 invalid because l is negative (violates rule 2)
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x)<span> 3,2,2,1/2 valid: meet the four rules</span>
xi)<span> 4,2,1,1/2 valid: meet the four rules</span>
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</span><span>xii) 2,1,-1,-1/2 valid meet the four rules</span>