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Ksju [112]
4 years ago
8

Which statement most accurately compares the temperature of the core of the sun to its surface

Chemistry
1 answer:
atroni [7]4 years ago
5 0
The core is more than 1000 times hotter than the surface. 
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What mass is contributed by Br-79?
satela [25.4K]

Answer:

Calculate the mass of BR -79? Bromine has 2 naturally occurring isotopes (Br-79 and Br-81) and has an atomic mass of 79.904 amu

Explanation:

if i get this wrong srry

6 0
3 years ago
What is the molarity of a solution containing 8.0 moles of solute in 120mL of solution?
Nataliya [291]
Answer:
200/3 M which is approximately equal to 66.6667 M

Explanation:
Molarity is defined as the number of moles of solute per liter of solution.

It can be calculated as follows:
molarity =  \frac{number of moles of solute}{liters of solution}

We are given that:
number of moles of solute = 8 moles
volume of solution = 120 ml = 0.12 liters

Substitute with the givens in the above equation to get the molarity as follows:
molarity = \frac{8}{0.12} =  \frac{200}{3} = 66.6667 M

Hope this helps :)
3 0
3 years ago
A hypothetical element has an atomic weight of 48.68 amu. It consists of three isotopes having masses of 47.00 amu, 48.00 amu, a
Morgarella [4.7K]

Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

As we are given that,

Average atomic mass = 48.68 amu

Mass of heaviest-weight isotope = 49.00 amu

Let the percentage abundance of heaviest-weight isotope = x %

Fractional abundance of heaviest-weight isotope = \frac{x}{100}

Mass of lightest-weight isotope = 47.00 amu

Percentage abundance of lightest-weight isotope = 10 %

Fractional abundance of lightest-weight isotope = \frac{10}{100}

Mass of middle-weight isotope = 48.00 amu

Percentage abundance of middle-weight isotope = [100 - (x + 10)] %  = (90 - x) %

Fractional abundance of middle-weight isotope = \frac{(90-x)}{100}

Now put all the given values in above formula, we get:

48.68=[(47.0\times \frac{10}{100})+(48.0\times \frac{(90-x)}{100})+(49.0\times \frac{x}{100})]

x=78\%

Therefore, the percent abundance of the heaviest isotope is, 78 %

5 0
3 years ago
Read 2 more answers
Which of the following is a true statement?
maria [59]

Answer:

the second one seems right :)

Explanation:

3 0
3 years ago
How do plants and animals help to maintain a balance of carbon dioxide in the atmosphere
Tom [10]
Well all I know that animals take in oxygen and take out carbon dioxide and plants take in carbon dioxide and take out oxygen
3 0
3 years ago
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