Answer: Theoretical Yield = 0.2952 g
Percentage Yield = 75.3%
Explanation:
Calculation of limiting reactant:
n-trans-cinnamic acid moles = (142mg/1000) / 148.16 = 9.584*10⁻⁴ mol
pyridium tribromide moles = (412mg/1000) / 319.82= 1.288*10⁻³ mol
- n-trans-cinnamic acid is the limiting reactant
The molar ratio according to the equation mentioned is equals to 1:1
The brominated product moles is also = 9.584*10⁻⁴ mol
Theoretical yield = (9.584*10⁻⁴ mol) * (Mr of brominated product)
= (9.584*10⁻⁴ mol) * (307.97) = 0.2952 g
Percentage Yield is : Actual Yield / Theoretical Yield = 0.2223/0.2952
= 75.3%
Answer:
Option (B) 6270J
Explanation:
The following were obtained from the question:
M = 100g
T1 = 30°C
T2 = 45°C
ΔT = 45 —30 = 15°C
C = 4.18J/g°C
Q=?
Q = MCΔT
Q = 100 x 4.18 x 15
Q = 6270J
Therefore, the total amount of heat absorbed is 6270J
Answer:
is the concentration of
in the solution.
Explanation:
![Ni^{2+}(aq) + 3 en\rightleftharpoons [Ni(en)_3]^{2+}(aq)](https://tex.z-dn.net/?f=Ni%5E%7B2%2B%7D%28aq%29%20%2B%203%20en%5Crightleftharpoons%20%5BNi%28en%29_3%5D%5E%7B2%2B%7D%28aq%29)
Concentration of nickel ion = ![[Ni^{2+}]=x](https://tex.z-dn.net/?f=%5BNi%5E%7B2%2B%7D%5D%3Dx)
Concentration of nickel complex= ![[[Ni(en)_3]^{2+}]=\frac{0.16 mol}{2 L}=0.08 mol/L](https://tex.z-dn.net/?f=%5B%5BNi%28en%29_3%5D%5E%7B2%2B%7D%5D%3D%5Cfrac%7B0.16%20mol%7D%7B2%20L%7D%3D0.08%20mol%2FL)
Concentration of ethylenediamine = ![[en]=\frac{0.80 mol}{2 L}=0.40 mol/L](https://tex.z-dn.net/?f=%5Ben%5D%3D%5Cfrac%7B0.80%20mol%7D%7B2%20L%7D%3D0.40%20mol%2FL)
The formation constant of the complex = 
The expression of formation constant is given as:
![K_f=\frac{[[Ni(en)_3]^{2+}]}{[Ni^{2+}][en]^3}](https://tex.z-dn.net/?f=K_f%3D%5Cfrac%7B%5B%5BNi%28en%29_3%5D%5E%7B2%2B%7D%5D%7D%7B%5BNi%5E%7B2%2B%7D%5D%5Ben%5D%5E3%7D)



is the concentration of
in the solution.
Answer:
NH2.
Explanation:
The mass of hydrogen in the sample = 1.525 - 1.333 = 0.192g.
Dividing the 2 masses by the relative atomic mass of hydrogen and nitrogen:
H: 0.192 / 1.008 = 0.1905
N: 1.333 / 14.007 = 0.09517
The ratio of N to H = 0.09517 : 0.1905
= 1 : 2.
So the empirical formula is NH2.