E and Dis determine the H
Moles of Hydrogen present: 100 / 2 = 50 moles
Moles of Nitrogen present: 200 / 28 = 7.14 moles
Hydrogen required by given amount of nitrogen = 7.14 x 3 = 21.42 moles
Hydrogen is excess so we will calculate the Ammonia produced using Nitrogen.
Molar ratio of Nitrogen : Ammonia = 1 : 2
Moles of ammonia = 7.14 x 2 = 14.28 moles
(1) CaCO3 is the correct answer.
The type of bond formed between Ca2+ and CO3 2- is ionic, and the type of bond formed between C and O is covalent.
Hope this helps~
Answer: option A) Mixtures may be composed of two or more elements, two or more compounds, or a combination of both.
Explanation:
A mixture is a combination of two or more substances mixed together and can be separated by physical methods.
A combination of two elements or compounds will yield chemical compounds NOT a mixture.
Thus, option A is false statement
Answer:
m = 19 grams
Explanation:
Given that,
No. of moles, n = 0.8
The molar mass of magnesium, M = 24.305 u
We need to find the mass of 0.80 moles of Mg. We know that given mass to the molar mass is equal to no of moles. Let the mass is m. So,
or
m = 19 grams
So, the mass of 0.8 moles of Mg is 19 grams.
