The answers are as follows,
1. 4.71 L,
2. 3.29 L,
3. 1634.6 torr
<u>Explanation:</u>
All the above problems can be sorted out using the Boyle's law represents the relationship between the volume and pressure.
It can be expressed as follows,
P1V1 = P2V2
Rearranging the above expression, we get,
1) The first case can be solved as,
![$V 2=\frac{921 \mathrm{mm} \mathrm{Hg} \times 3.89 \mathrm{L}}{760 \mathrm{mm} \mathrm{Hg}}=4.71 \mathrm{L}](https://tex.z-dn.net/?f=%24V%202%3D%5Cfrac%7B921%20%5Cmathrm%7Bmm%7D%20%5Cmathrm%7BHg%7D%20%5Ctimes%203.89%20%5Cmathrm%7BL%7D%7D%7B760%20%5Cmathrm%7Bmm%7D%20%5Cmathrm%7BHg%7D%7D%3D4.71%20%5Cmathrm%7BL%7D)
2) The second case can be solved as,
![$V 2=\frac{25 L \times 600 \text { torr}}{4560 \text { torr}}=3.29 L](https://tex.z-dn.net/?f=%24V%202%3D%5Cfrac%7B25%20L%20%5Ctimes%20600%20%5Ctext%20%7B%20torr%7D%7D%7B4560%20%5Ctext%20%7B%20torr%7D%7D%3D3.29%20L)
3) The third case can be solved as,
![$P 2=\frac{7.43 L \times 1100 \text { torr}}{5 L}=1634.6 \text { torr}](https://tex.z-dn.net/?f=%24P%202%3D%5Cfrac%7B7.43%20L%20%5Ctimes%201100%20%5Ctext%20%7B%20torr%7D%7D%7B5%20L%7D%3D1634.6%20%5Ctext%20%7B%20torr%7D)
Thus the answers for all the three cases are found as,
1. 4.71 L,
2. 3.29 L,
3. 1634.6 torr respectively
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Man is naturally surrounded by many natural and artificial radioactive sources which give out radiations on a daily basis. Although most people believe that the natural radiation are at levels that are not dangerous, scientific studies had found out that this is not true; some of the radiations are given out at the rate that are harmful to humans.<span />
Answer:
r = 0.0018 molxL⁻¹xs⁻¹
t = 472.22 s
Explanation:
The rate of the reaction is given by:
![r = k[A]^n](https://tex.z-dn.net/?f=r%20%3D%20k%5BA%5D%5En)
Where <em>r</em> is the rate, <em>k</em> is the rate constant, <em>[A]</em> is the initial concentration of the reactant and <em>n</em> is the order of the reaction. So, for this problem:
r = 0.0018x[1.70]⁰
r = 0.0018 molxL⁻¹xs⁻¹
The rate is also the variation of the concentration divided by the time. So, for the half-life, the concentration will be decreased by half and will be 0.85 mol/L. So the variation will be 1.70 - 0.85 = 0.85 mol/L. So:
0.0018 = 0.85/t
t = 0.85/0.0018
t = 472.22 s