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3 years ago

Yoshi is 5% taller today than she was one year ago. Her current height is 168 cm. How tall was she one year ago

2 answers:

8 0

5% of 168:
simplify 5%=1/20
1/20 of 168=8.4
so this year Yoshi is taller than last year 8.4cm
->168-8.4=159.6cm
Yoshi was 159.6cm last year

NemiM [27]3 years ago

5 0

155.6 CM
I divided 168 by 100 to find 1% then i got 1.68cm then I times that by 5 to find 5% which was 8.4cm. Finally I subtracted 168 and 8.4 to get 155.6 CM
I hope that helped :)

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2 years ago

Solid fats are more likely to raise blood cholesterol levels than liquid fats. Suppose a nutritionist analyzed the percentage of

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Answer:

$t = 31.29$

Step-by-step explanation:

Given

$\begin{array}{ccccccc}{Stick} & {25.8} & {26.9} & {26.2} & {25.3} & {26.7}& {26.1} \ \\ {Liquid} & {16.9} & {17.4} & {16.8} & {16.2} & {17.3}& {16.8} \ \end{array}$

Required

Determine the test statistic

Let the dataset of stick be A and Liquid be B.

We start by calculating the mean of each dataset;

$\bar x =\frac{\sum x}{n}$

n, in both datasets in 6

For A

$\bar x_A =\frac{25.8+26.9+26.2+25.3+26.7+26.1}{6}$

$\bar x_A =\frac{157}{6}$

$\bar x_A =26.17$

For B

$\bar x_B =\frac{16.9+17.4+16.8+16.2+17.3+16.8}{6}$

$\bar x_B =\frac{101.4}{6}$

$\bar x_B =16.9$

Next, calculate the sample standard deviation

This is calculated using:

$s = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}$

For A

$s_A = \sqrt{\frac{\sum(x - \bar x_A)^2}{n-1}}$

$s_A = \sqrt{\frac{(25.8-26.17)^2+(26.9-26.17)^2+(26.2-26.17)^2+(25.3-26.17)^2+(26.7-26.17)^2+(26.1-26.17)^2}{6-1}}$

$s_A = \sqrt{\frac{1.7134}{5}}$

$s_A = \sqrt{0.34268}$

$s_A = 0.5854$

For B

$s_B = \sqrt{\frac{\sum(x - \bar x_B)^2}{n-1}}$

$s_B = \sqrt{\frac{(16.9 - 16.9)^2+(17.4- 16.9)^2+(16.8- 16.9)^2+(16.2- 16.9)^2+(17.3- 16.9)^2+(16.8- 16.9)^2}{6-1}}$

$s_B = \sqrt{\frac{0.92}{5}}$

$s_B = \sqrt{0.184}$

$s_B = 0.4290$

Calculate the pooled variance

$S_p^2 = \frac{(n_A - 1)*s_A^2 + (n_B - 1)*s_B^2}{(n_A+n_B-2)}$

$S_p^2 = \frac{(6 - 1)*0.5854^2 + (6 - 1)*0.4290^2}{(6+6-2)}$

$S_p^2 = \frac{2.6336708}{10}$

$S_p^2 = 0.2634$

Lastly, calculate the test statistic using:

$t = \frac{(\bar x_A - \bar x_B) - (\mu_A - \mu_B)}{\sqrt{S_p^2/n_A +S_p^2/n_B}}$

We set

$\mu_A = \mu_B$

So, we have:

$t = \frac{(\bar x_A - \bar x_B) - (\mu_A - \mu_A)}{\sqrt{S_p^2/n_A +S_p^2/n_B}}$

$t = \frac{(\bar x_A - \bar x_B) }{\sqrt{S_p^2/n_A +S_p^2/n_B}}$

The equation becomes

$t = \frac{(26.17 - 16.9) }{\sqrt{0.2634/6 +0.2634/6}}$

$t = \frac{9.27}{\sqrt{0.0878}}$

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Answer: There are $198$ children at the circus show.

Step-by-step explanation:

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Since $\frac{2}{5}$ of the remaining number of spectaros are women and there are a total of 132 women, we can write the following equation:

$(\frac{2}{5})(\frac{3}{4}x)=132$

Solving for "x", we get:

$x=(132)(\frac{20}{6})\\\\x=440$

Therefore, we get that "c" is:

$c=440-\frac{1}{4}(440)-132\\\\c=198$

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3 years ago

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lilavasa [31]

Answer:

Correct option is:

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Step-by-step explanation:

A hypothesis for the proportion of people who include locally grown foods in their diets can be defined as:

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Hₐ: The proportion of people who include locally grown foods in their diets is difference from p.

The decision rule can be based on the 95% confidence interval.

If the confidence interval consists the hypothetical value of the true proportion then the null hypothesis will be accepted or else the null hypothesis will be rejected.

The 95% confidence interval for the proportion of all people in the country who try to include locally grown foods in their diets is given as (0.70, 0.76).

This interval implies that there is 0.95 probability that the true proportion of people who include locally grown foods in their diets is between 70% and 76%.

Assuming that the claim made was supported by the 95% confidence interval.

The claim should be:

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Because the 95% confidence interval defines the range of the true proportion as 70% to 76%. Most of the values are below 75%.

Thus, the correct option is:

"Less than 75% of all people in the country try to include locally grown foods in their diets."

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