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sertanlavr [38]
3 years ago
15

Find the quotient. 10669/7

Mathematics
2 answers:
Sedaia [141]3 years ago
8 0

10669 divided by 7 is about 1524.143 or 154 and 1/7 as a mixed number

hram777 [196]3 years ago
6 0

The quotient of these two numbers is 1524.14.

To find the quotient of any two numbers, we are simply looking to divide. Divide 10669 by 7 and you get roughly 1524.14, when rounded to two decimal places.

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A healthcare provider monitors the number of CAT scans performed each month in each of its clinics. The most recent year of data
Rasek [7]

Answer: a. 1.981 < μ < 2.18

              b. Yes.

Step-by-step explanation:

A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.

First, we calculate mean of the sample:

\overline{x}=\frac{\Sigma x}{n}

\overline{x}=\frac{2.31=2.09+...+1.97+2.02}{12}

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Now, we estimate standard deviation:

s=\sqrt{\frac{\Sigma (x-\overline{x})^{2}}{n-1} }

s=\sqrt{\frac{(2.31-2.08)^{2}+...+(2.02-2.08)^{2}}{11} }

s = 0.1564

For t-score, we need to determine degree of freedom and \frac{\alpha}{2}:

df = 12 - 1

df = 11

\alpha = 1 - 0.95

α = 0.05

\frac{\alpha}{2}= 0.025

Then, t-score is

t_{11,0.025} = 2.201

The interval will be

\overline{x} ± t.\frac{s}{\sqrt{n} }

2.08 ± 2.201\frac{0.1564}{\sqrt{12} }

2.08 ± 0.099

The 95% two-sided CI on the mean is 1.981 < μ < 2.18.

B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.

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3 years ago
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Answer:

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Help me I need help ASAP will <br> Give BRAINLIEST
makvit [3.9K]

Answer:

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rational: all but pi

Integers: 20,-9

Whole, 20,-9, radical 16

Natural: 20

Irrational: pi

Step-by-step explanation:

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