To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
Yy=5(xx)
works because lets say you need 3 cups of sugar. 3x5 is 15 which is exactly the number of cups of flour you would need
Step-by-step explanation:
complementry
since the angle 1 and 2 both measures 90⁰
Answer:
3x ≥ 45
15, 20 , 25
Step-by-step explanation:
Let's call the number of bars Renee sold as " x "
Let's call the number of bars Robin sold as " y "
Robins, y, sold two times as many bars as Renee, x
That means Robin sold 2 times x or 2x
So y = 2x
The sum of bars Renee, x, and Robin, 2x, sold together are no less than 45
No less than 45 means the number of bars have to be greater than or equal to 45
x + 2x ≥ 45
3x ≥ 45
x ≥ 15
Renee can sell, 15, 20, or 25 bars . (just has to be bigger or equal to 15)
If my answer is incorrect, pls correct me!
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-Chetan K
A= 1/360 m•pi r^2
11/2= 1/360 m• pi (3)^2
11/2= 1/360 m• pi • 9
Divide 360 by 9
11/2= 1/40 m pi
Cross multiply
440=2pi m
Divide both sides by 2pi
m= 70.02817 degrees round if necessary
