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disa [49]
2 years ago
15

Classify ∠1 and ∠2 using all names that apply

Mathematics
2 answers:
Vinvika [58]2 years ago
6 0

Step-by-step explanation:

complementry

since the angle 1 and 2 both measures 90⁰

lilavasa [31]2 years ago
3 0

Answer: Choice 2 Adjacent and Choice 4 Supplementary

Step-by-step explanation:

Here, we are given four choices, and I will be defining each of them.

  • Vertical angles: two angles that are opposite to each other which was formed by two intersecting lines.
  • Adjacent angles: two angles that share one common vertex and "arm"
  • Complementary angles: two angles that add up to 90°
  • Supplementary angles: two angles that add up to 180°

-----------------------------------------------------------------------------------------------

We can see from the figure given

Both angles are 90°, so ∠1+∠2=90+90=180°

Which is supplementary.

We can see from the figure given

Both angles share a common arm and vertex

Which is adjacent

Hope this helps!! :)

Please let me know if you have any questions

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Mr lance designed a class banner shaped like a the polygon shown. What is the name of the polygon?
Scorpion4ik [409]

Answer:

hexagon

Step-by-step explanation:

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7 0
2 years ago
Solve <br> X^2+5x+6=0<br><br> Please help
gogolik [260]

Answer: x= 3,2

Step-by-step explanation:

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

5 0
3 years ago
Find z1z2 if z1 = 2/5(cos63° + isin63°) and z2 = 10/3(cos117° + isin117°).
Airida [17]

Answer:

-10/3 is the answer

Step-by-step explanation:

Given are two complex numbers as

z1=\frac{2}{5} (cos63  + isin63)\\z2=\frac{10}{3} (cos 117 + isin117})

Recall Demoivre theorem as

(cosA+isinA)(cos A+isin B) = cos(A+B)+isin(A+B)

Hence here we have sum of angles  as

A+B = 63+117 =180

z1z2=\frac{2}{5} \frac{10}{3} (cos180+isin180)

=\frac{-10}{3}

Since sin180=0 and cos 180=-1

7 0
3 years ago
Just need help with 4. Please
konstantin123 [22]

Answer:

11 3/5*9*12 1/2=1,305

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Hope I helped.

Step-by-step explanation:

6 0
3 years ago
Help me with the work
Tpy6a [65]

Answer:

Option B k > 0

Step-by-step explanation:

we know that

Observing the graph

The slope of the line is positive

The y-intercept is negative

we have

3y-2x=k(5x-4)+6\\ \\3y=5kx-4k+6+2x\\ \\3y=[5k+2]x+(6-4k)\\ \\y=\frac{1}{3}[5k+2]x+(2-\frac{4}{3}k)

The slope of the line is equal to

m=\frac{1}{3}[5k+2]

Remember that the slope must be positive

so

5k+2> 0\\ \\k > -\frac{2}{5}

The value of k is greater than -2/5

Analyze the y-intercept

(2-\frac{4}{3}k) < 0\\ \\ 2 < \frac{4}{3}k\\ \\1.5 < k\\ \\k > 1.5

1.5 is greater than zero

so

the solution for k is the interval ------> (1.5,∞)

therefore

must be true

k > 0

5 0
3 years ago
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