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2 years ago

Classify ∠1 and ∠2 using all names that apply

Mathematics

2 answers:

Vinvika [58]2 years ago

6 0

Step-by-step explanation:

complementry

since the angle 1 and 2 both measures 90⁰

lilavasa [31]2 years ago

3 0

Answer: Choice 2 Adjacent and Choice 4 Supplementary

Step-by-step explanation:

Here, we are given four choices, and I will be defining each of them.

Vertical angles: two angles that are opposite to each other which was formed by two intersecting lines.
Adjacent angles: two angles that share one common vertex and "arm"
Complementary angles: two angles that add up to 90°
Supplementary angles: two angles that add up to 180°

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We can see from the figure given

Both angles are 90°, so ∠1+∠2=90+90=180°

Which is supplementary.

We can see from the figure given

Both angles share a common arm and vertex

Which is adjacent

Hope this helps!! :)

Please let me know if you have any questions

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Read 2 more answers

Consider M, N, and P. collinear points on MP.

Kobotan [32]

Answer:

See explanation

Step-by-step explanation:

There are three possible cases:

1. Point N lies between M and P, then MN + NP = MP. Consider needed difference:

$\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MN}{NP}-\dfrac{MN}{MN+NP}=\dfrac{MN(MN+NP)-MN\cdot NP}{NP(MN+NP)}=\\ \\=\dfrac{MN^2+MN\cdot NP-MN\cdot NP}{NP(MN+NP)}=\dfrac{MN^2}{NP(MN+NP)}$

2. Point N lies to the right from point P, then MP + PN = MN. Consider needed difference:

$\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MP+PN}{NP}-\dfrac{MP+PN}{MP}=\dfrac{MP}{NP}+1-1-\dfrac{NP}{MP}=\dfrac{MP^2-NP^2}{NP\cdot MP}$

3. Point N lies to the left from point M, then NM + MP = NP. Consider needed difference:

$\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MN}{MN+MP}-\dfrac{MN}{MP}=\dfrac{MN\cdot MP-MN(MN+MP)}{MP(MN+MP)}=\\ \\=\dfrac{MN\cdot MP-MN^2-MN\cdot MP}{MP(MN+MP)}=\dfrac{-MN^2}{MP(MN+MP)}$

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2 years ago

1 + 1 I dont know how to solve this problem please help me...

Deffense [45]

Answer:

1+1= 2

Step-by-step explanation:

or sometimes people say 11, but irl its 2

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