I can’t see the picture so if you just want to comment and put it there I can help :)
Surface area = 17*(sqrt(1155) + 19)
h^2 = 19^2 - 17^2/4
=> h = sqrt(4*19^2 - 17^2)/2 = sqrt(1155)/2
Surface area = 4(1/2*h*17) + 17*19 = 17(sqrt(1155) + 19)
The probability is 1/5 to get a red ball in 1st draw and a white ball in 2nd draw.
<u>Step-by-step explanation:</u>
- There are 1 red ball and 4 white balls in a box.
- The total number of balls in the box = 1 red + 4 white = 5 balls.
The two balls are drawn without replacement.
<u>Drawing the first ball :</u>
The first draw should be a red ball.
The probability to get a red ball = No.of red balls / Total balls in the box.
We know that, No. of red balls is 1 and total balls in the box is 5.
P(red ball) = 1/5
<u>Drawing the second ball :</u>
The second draw should be a white ball.
The probability to get white ball = No.of white balls / Total balls in the box.
We know that,
No. of white balls is 4.
The total balls in the box after the first draw will be 4 balls.
P(white ball) = 4/4
The probability of getting a red ball on the first drawn and a white ball on the second draw = P(red ball) × P(white ball)
⇒ (1/5) × (4/4)
⇒ 4/20
⇒ 1/5
Therefore, the probability is 1/5 to get a red ball in 1st draw and a white ball in 2nd draw.
Answer: −(b+4)(2b−3)
Step-by-step explanation:
1. Factor out the negative sign.
−(2b^2+5b−12)
2. Split the second term in 2b^2+5b−12 into two terms.
−(2b^2+8b−3b−12)
3.Factor out common terms in the first two terms, then in the last two terms.
−(2b(b+4)−3(b+4))
4. Factor out the common term b+4b+4b+4.
−(b+4)(2b−3)
