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monitta
3 years ago
8

Find the prime factorization of 24. Make sure to show all of your work.

Mathematics
2 answers:
miss Akunina [59]3 years ago
6 0

Answer:

2^3*3

Step-by-step explanation:

So the prime factorization of 24 is 24 = 2 · 2 · 2 · 3 = 23 · 3.

blondinia [14]3 years ago
6 0

Answer:

2^3*3

Step-by-step explanation: So the prime factorization of 24 is 24 = 2 · 2 · 2 · 3 = 23 · 3.

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Kari drew two parallel lines PQ and RS intersected by a transversal KL, as shown below:
Arlecino [84]
Given that PQ and RS are drawn with KL as tranversal intersecting PQ at M and RS at point N. Angle QMN is congruent to angle LNS because they are alternate to each other. The theorem that Kari can use to show that the meansure of QML is supplementary to the measure of angle SNK is Alternate Exterior Angles Theorem.
This is because angle KNR is equal to QML by alternate exterior angles theorem so is angle MLP and SNK 
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3 years ago
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How to solve 5x+8y=14 And 4x=24 by substitution
Virty [35]
5x+8y=14 \\ 4x=24 \\ \\ \hbox{solve the 2nd equation for x:} \\ 4x=24 \\
x=6 \\ \\
\hbox{substitute 6 for x in the 1st equation:} \\
5 \times 6+8y=14 \\
30+8y=14 \\
8y=14-30 \\
8y=-16 \\
y=-2 \\ \\ \hbox{the answer:} \\ x=6 \\ y=-2
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3 years ago
Find the volume and tell me if cavalieri's principle applies to the 2 figures. Show work
Hunter-Best [27]

Answer:

960vol cavalieri's principle applies

Step-by-step explanation:

8x6x20 for vol

"Cavalieri's Principle. If, in two solids of equal altitude, the sections made by planes parallel to and at the same distance from their respective bases are always equal, then the volumes of the two solids are equal "(Kern and Bland 1948)

both same height both equal in all ways

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3 years ago
Geometry - Unit 2 Readiness Assessment
Lyrx [107]

Answer:

1. A. They are similar because polygon G'H'J'K' can be obtained from polygon GHJK by a sequence of transformation

2. B. Reflection across the y-axis

Step-by-step explanation:

1) The coordinates of the sides of the polygon are;

G(-6, 8), H(-2, 4), J(-4, 2), and K(-8, 2)

G'(3, -1), H'(1, -3), J'(2, -4), K'(4, -4)

The length, l, of the sides are;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

Length of GH = √((8 - 4)² + ((-6) - (-2))²)  = 4·√2

Length of HJ = √((2 - 4)² + ((-4) - (-2))²)  = 2·√2

Length of JK = √((2 - 2)² + ((-4) - (-8))²)  = 4

Length of KG = √((2 - 8)² + ((-8) - (-6))²)  = 2·√10

Similarly, we have;

Length of G'H' = √(((-3) - (-1))² + (1 - 3)²)  = 2·√2

Length of H'J' = √(((-3) - (-4))² + (1 - 2)²)  = √2

Length of J'K' = √(((-4) - (-4))² + ((4)- 2)²)  = 2  

Length of K'G' = √(((-4) - (-1))² + ((4) - 3)²)  = √10  

Therefore, the polygon G'H'J'K' can be obtained from the polygon GHJK by scaling down by a factor of 2, and the two polygons are similar

2) Given that the coordinates of figure 2 are (-2, 3) (-3, 5), (-4, 1), and (-6, 1), while the corresponding coordinates of figure 3 are (2, 3), (3, 5), (4, 1), and (6, 1) which is equivalent to a transformation from (x, y) to (-x, y) which is the  transformation involved in a reflection across the y-axis

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2 years ago
How many girls played for the Newcastle T-ball team?
mart [117]
14 Girls in Newcastle because if you add 14 Newcastle + 6 Sunderland= 20
5 0
3 years ago
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