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AlekseyPX
3 years ago
15

The admission fee at a small is $1.50 for children and $4.00 for adults. On a certain day, 2200 people enter the fair and $5050

is collected.
How many children and how many adults attended?

Solve using systems of equations.
Mathematics
1 answer:
Finger [1]3 years ago
4 0
x-\ amount\ of\ children\\
y-\ amount\ of\ adults\\\\
 \left \{ {{x+y=2200\ \ |*(-4)} \atop {1,5x+4y=5050}} \right.\\\\  \left \{ {{-4x-4y=-8800} \atop {1,5x+4y=5050}} \right.\\\\ +-------\\
-2,5x=-3750\ \ |Divide\ by\ -2,5\\
x=1500\\
y=2200-1500\\
y=700\\\\There\ were\ 1500\ children\ and\ 700\ adults.
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3x2−21x+3=0

Step 1: Use quadratic formula with a=3, b=-21, c=3.

x=−b±√b2−4ac2a

x=−(−21)±√(−21)2−4(3)(3)2(3)

x=21±√4056

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answer

x=72+32√5 or x=72+−32√5


4 0
3 years ago
A Recipe for party mix calls for 3/4 cup of cereal , 1/4 Cup of walnuts, 5/8 cup of crackers , and 1/2 cup of raisins . determin
yuradex [85]
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4 0
3 years ago
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Which of the following is a factor of 2x2–7x–15?
zimovet [89]

Answer:

hello :  x - 5

Step-by-step explanation:

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5 0
2 years ago
Please help me ASAP!!! could someone help me do my geometry?
elena-14-01-66 [18.8K]

Answer:

9. m(YZ) = 102°

10. m(JKL) = 192°

11. m<GHF = 75°

Step-by-step explanation:

9. First, find the value of x

4x + 3 = 3x + 15 (inscribed angle that are subtended by the same arc are equal based on the inscribed angle theorem)

Collect like terms

4x - 3x = -3 + 15

x = 12

4x + 3 = ½(m(YZ)) (inscribed angle of a circle = ½ the measure of the intercepted arc)

Plug in the value of x

4(12) + 3 = ½(m(YZ))

48 + 3 = ½(m(YZ))

51 = ½(m(YZ))

Multiply both sides by 2

51*2 = m(YZ)

102 = m(YZ)

m(YZ) = 102°

10. First, find the value of x.

7x + 5 + 6x + 6 = 180° (opposite angles in an inscribed quadrilateral are supplementary)

Add like terms

13x + 11 = 180

13x = 180 - 11

13x = 169

x = 169/13

x = 13

7x + 5 = ½(m(JKL)) (inscribed angle of a circle = ½ the measure of the intercepted arc)

Plug in the value of x

7(13) + 5 = ½(m(JKL))

96 = ½(m(JKL))

Multiply both sides by 2

2*96 = m(JKL)

m(JKL) = 192°

11. First, find x.

5x + 15 = ½(11x + 18) (inscribed angle of a circle = ½ the measure of the intercepted arc)

Multiply both sides by 2

2(5x + 15) = 11x + 18

10x + 30 = 11x + 18

Collect like terms

10x - 11x = -30 + 18

-x = -12

Divide both sides by -1

x = 12

m<GHF = 5x + 15

Plug in the value of x

m<GHF = 5(12) + 15

m<GHF = 60 + 15

m<GHF = 75°

4 0
2 years ago
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