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Alexandra [31]
3 years ago
11

Each equation in a system of linear equations has the same slope. What are the possible solutions the system could have?

Mathematics
1 answer:
Kazeer [188]3 years ago
3 0

Answer:

A. The system could have no solution or infinitely many solutions.

Step-by-step explanation:

Parallel lines have the same slope, meaning that they cannot intersect. So, the system can either have no solution (no intersection), or infinite possible solutions (the same line).

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PLEASE HELP!!! Division
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The answer is 36/49.

You take the second fraction and flip it (it will be 12/14) and you multiply straight across. You get 72/98. You simplify it by finding it's greatest common factor (in this case it is 2) so you divide it the numerator and the denominator by 2. You get 36/49.
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3 years ago
Can someone please help me with this question
Elina [12.6K]

Answer:

The answer should be: B

I think it's B because there are 2 cups of water (2c) and 7 bottles of water (7w) which costs $16 so that would be 2c +7w=16. Also for the other one, it's 3 cups (3c) and 8 bottles of water (8W) and the cost is $19 so that would be

3c + 8w =19

Step-by-step explanation: Hope this helps and gl :))

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She realized that she was and she indeed was so she did and did.
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sladkih [1.3K]

Answer:

216

Step-by-step explanation:

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3 years ago
Read 2 more answers
Help with this one because I do not know how to do perpendicular plz put explanation with steps worth 50!
Yuri [45]

Answer:

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line 2x-3y=12 is 3x+2y=34  

Step-by-step explanation:

Given:  

2x-3y=12  

To Find:  

Equation of line passing through ( 16, -7) and is perpendicular to the line  

2x-3y=12  

Solution:  

2x-3y=12 ...........Given  

\therefore y=\dfrac{2}{3}\times x-4

Comparing with,  

y=mx+c  

Where m =slope  

We get  

Slope = m1 = \dfrac{2}{3}  

We know that for Perpendicular lines have product slopes = -1.

m1\times m2=-1

Substituting m1 we get m2 as

\dfrac{2}{3}\times m2=-1\\\\m2=-\dfrac{3}{2}

Therefore the slope of the required line passing through (16 , -7) will have the slope,

m2=-\dfrac{3}{2}  

Now the equation of line in slope point form given by  

(y-y_{1})=m(x-x_{1})  

Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,  

(y-(-7))=-\dfrac{3}{2}\times (x-16)\\\\2y+14=-3x+48\\3x+2y=34......Equation\ of\ line  

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line  2x-3y=12 is

3x+2y=34  

3 0
3 years ago
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