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3 years ago

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A student fit the line shown below to the data in the scatter plot. Which statement about the student's line is true?

1 answer:

Furkat [3]3 years ago

8 0

Answer:

C. It is not a good fit because there are no points on the line.

Step-by-step explanation:

In order for a line to be a good fit for a data set represented as a scatterplot, the line must follow the general trend of the data in the scatterplot. This line does not follow the general trend of the data on the scatterplot, thus option (C) is the best statement to describe the situation.

C. It is not a good fit because there are no points on the line.

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The Venn diagram shows three types of numbers: odd (O), even (E), and prime (P).

Viefleur [7K]

Answer:

Null set

Step-by-step explanation:

Odd(0)

Even (E)

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3 years ago

you have a case of our mom's each one weighs 1.4 pounds and weight of 28 lb how many watermelons do you have

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Answer:

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Step-by-step explanation:

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3 years ago

Write and equati9n of a l8ne that passes through (1,-2) and is perpendicular to -4x+7y=21

yarga [219]

Given:

A line passes through (1,-2) and is perpendicular to $-4x+7y=21$ .

To find:

The equation of that line.

Solution:

We have, equation of perpendicular line.

$-4x+7y=21$

Slope of this line is

$m_1=-\dfrac{\text{Coefficient of x}}{\text{Coefficient of y}}$

$m_1=-\dfrac{-4}{7}$

$m_1=\dfrac{4}{7}$

Product of slope of two perpendicular lines is -1.

$m_1\times m_2=-1$

$\dfrac{4}{7}\times m_2=-1$

$m_2=-\dfrac{7}{4}$

Now, slope of required line is $-\dfrac{7}{4}$ and it passes through (1,-2). So, the equation of line is

$y-y_1=m(x-x_1)$

where, m is slope.

$y-(-2)=-\dfrac{7}{4}(x-1)$

$4(y+2)=-7(x-1)$

$4y+8=-7x+7$

$4y+7x=7-8$

$7x+4y=-1$

Therefore, the equation of required line is $7x+4y=-1$ .

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steposvetlana [31]

Answer:

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Step-by-step explanation:

can also be written as 3/2 as a fraction!

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