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At STP, the volume of Cl2 is 22.4 L/mol.
11.5 L Cl2 * (1 mol Cl2/ 22.4 L Cl2)= 115/224 mol Cl2.
115/224 mol Cl2* (70.90 g Cl2/ 1 mol Cl2)= 36.4 g Cl2.
The final answer is 36.4 g Cl2.
Hope this helps~
<span>When ammonium is dissolved in wated, we have,
NH3 + H2O >> NH4+ + OHÂŻ
pOH = -log[OH-]
pOH = -log[2.25x10^-2]
pOH = 1.6478
Since pH + pOH=14. Therefore pH = 14 - pOH = 14 - 1.648 = 12.3522.
[H+]=10^-pH
[H+]=10^(-12.3522)
[H+]= 4.3250 * 10 ^(-5)</span>
Answer:
ok
Explanation:
do you still need the answer sorry