Which number is divisible by 3 and 5 a. 130 b. 325 c. 4113 d. 2040

1 answer:

8 0

A number that is divisible by 5 is one that ends with either a 5 or 0. To find a number that is divisible by 3 add up the digits and if they are divisible by 3, the number also is. That rules c out because it doesn't end with a 5 or 0. 130 and 325 won't work because they are not divisible by 3. The answer would be 2040.

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Find k if (x+1) 2x^3+kx^2+1

Viktor [21]

<h2>Question:</h2>

Find k if (x+1) is a factor of 2x³ + kx² + 1

<h2>Answer:</h2>

k = 1

<h2>Step-by-step explanation:</h2>

The factor of a polynomial F(x) is another polynomial that divides evenly into F(x). For example, x + 3 is a factor of the polynomial x² - 9.

<em>This is because;</em>

i. x² - 9 can be written as (x - 3)(x + 3) which shows that both (x - 3) and (x + 3) are factors.

ii. If x = -3 is substituted into the polynomial x² - 9, the result gives zero. i.e

=> (-3)² - 9

=> (9) - 9 = 0

Therefore, if (x + a) is a factor of a polynomial, substituting x = -a into the polynomial should result to zero. This also means that, if x - a is a factor of a polynomial, substituting x = a into the polynomial should give zero.

<em><u>From the question</u></em>

Given polynomial: 2x³ + kx² + 1

Given factor: x + 1.

Since x + 1 is a factor of the polynomial, substituting x = -1 into the polynomial should give zero and from there we can calculate the value of k. i.e

2(-1)³ + k(-1)² + 1 = 0

2(-1) + k(1) + 1 = 0

-2 + k + 1 = 0

k - 1 = 0

k = 1

Therefore the value of k is 1.

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3 years ago

On a piece of paper graph y+ 2 < 1/4 x - 1

xeze [42]

this is your answer, hope this helps