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The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviation of 600 hours. If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is closest to? Assuming percentile = 95%
Answer:
0.125
Step-by-step explanation:
Assuming for 95%
z score for 95th percentile = 1.645
We find the Probability using z table.
P(z = 1.645) = P( x ≤ 7000)
= P(x<Z) = 0.95
After 7000 hours = P > 7000
= 1 - P(x < 7000)
= 1 - 0.95
= 0.05
If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is calculated as:
(P > 7000)³
(0.05)³ = 0.125
Answer:
question
Step-by-step explanation:
what was the question? <3
Answer:
3.802e+6 miles
Step-by-step explanation:
mark me brainlist
Answer:
h < 7
Step-by-step explanation:
-8 < -4h + 20
4h < 28 / : 4
h < 7
Answer:
300
Step-by-step explanation:
Sum the parts of the ratio : 3 + 2 = 5 parts
Divide the number of appointments by 5 to find the value of one part of the ratio, that is
= 100 ← value of 1 part of the ratio
The mums consisted of 3 parts, hence
3 × 100 = 300 ← appointments with mums