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KiRa [710]
4 years ago
14

The sum of 14 and a number is equal to17

Mathematics
1 answer:
larisa86 [58]4 years ago
4 0
The number would be three

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How to solve 3(×-5)-5=23​
USPshnik [31]

Step 1: Simplify both sides of the equation.

3(x−5)−5=23

(3)(x)+(3)(−5)+−5=23(Distribute)

3x+−15+−5=23

(3x)+(−15+−5)=23(Combine Like Terms)

3x+−20=23

3x−20=23

Step 2: Add 20 to both sides.

3x−20+20=23+20

3x=43

Step 3: Divide both sides by 3.

3x /3  =  43 /3

x= 43 /3

4 0
3 years ago
Read 2 more answers
In triangle ABC, line A.B.=CB Angle ABC equals 4X -3, and angle CAB equals X -3, what is angle ACB
Soloha48 [4]

Answer:

∠ACB = 28.5

Step-by-step explanation:

In triangle ABC,

angle CAB = x-3

angle ABC = 4X-3

It is also given that AB=CB

We know that if two sides of any triangle are equal then corresponding sides must also be equal.

Hence

angle ACB = angle CAB

angle ACB = x-3    {Given that angle CAB = x-3 }

We know that sum of all three angles of a triangle is 180 degree so let's add given angles

angle ACB + angle CAB + angle ABC = 180

(x-3) + (x-3) + (4x-3) = 180

x-3 + x-3 + 4x-3 = 180

6x-9 = 180

6x = 180+9

6x = 189

x = 189/9

x= 31.5

Now plug value of x into

angle ACB = x-3 = 31.5-3 = 28.5

Hence final answer is

∠ACB = 28.5


3 0
3 years ago
Sample Response: You would graph the equation f(x) = –x + 3 for input values less than 2. There would be an open circle at the p
fgiga [73]

Answer:

Step-by-step explanation:

What did you include in your response? Check all that apply.

There would be an open circle at (2, 1).  <u>Yes</u>

There would be a closed circle at (2, 3).  <u>Yes</u>

There would be an open circle at (4, 3).  <u>Yes</u>

There would be a closed circle at (4, −4).  <u>Yes</u>

Endpoints that are not included in the domain of a particular piece of a function are represented by an open circle.  <u>Yes</u>

7 0
3 years ago
Someone help me with this I will make you brain
hram777 [196]

Step-by-step explanation:

let's look at the full numbers under the square roots when bringing the external factors back in :

sqrt(9×9×2) - sqrt(3×3×7) + sqrt(8) - sqrt(28)

and let's present these numbers as the product of their basic prime factors

sqrt(3×3×3×3×2) - sqrt(3×3×7) + sqrt(2×2×2) - sqrt(2×2×7)

now we see that we have 2 pairs of square roots : 1 pair ends with a factor of 2, and one pair with a factor of 7.

let's combine these

sqrt (3×3×3×3×2) + sqrt(2×2×2) - sqrt(3×3×7) - sqrt (2×2×7)

and now we move the factors of 2 and 7 back out in front (of course, we need to apply the square root on these factors) :

9×sqrt(2) + 2×sqrt(2) - 3×sqrt(7) - 2×sqrt(7) =

= (9+2)×sqrt(2) - (3+2)×sqrt(7) = 11×sqrt(2) - 5×sqrt(7)

and that is the first answer option.

5 0
3 years ago
Help please<br> 8. What is mZHTA?
klemol [59]

Answer:

67

Step-by-step explanation:

6 0
3 years ago
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