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8_murik_8 [283]
4 years ago
11

Amir's checking account charges a $9.75 monthly service fee and a $0.12 per-check fee. If Amir writes 15 checks per month, shoul

d he switch to a checking account that charges an $11.50 monthly service fee and no per-check fee
Mathematics
1 answer:
weqwewe [10]4 years ago
5 0

0.12(15) = 1.80
1.80 + 9.75 = 11.55
Yes Amir should switch because it's a nickel less
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masha68 [24]

Given:

-3x+2b>8

To find:

The value of x.

Solution:

We have,

-3x+2b>8

To find the value of x, we need to isolate x on one side.

Subtract 2b from both sides.

-3x>8-2b

Divide both sides by -3. On multiplying or dividing an inequality by a negative number, we need to change the sign of inequality.

\dfrac{-3x}{-3}

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The required inequality for x is x.

Therefore, the correct option is A.

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F is inversely proportional to d2<br> When F=12, d=3<br> Work out F when d=6
Thepotemich [5.8K]

Step-by-step explanation:

F -------> 1/d²

12 -------> 1/3²

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3----->1/6²

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3 years ago
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Arrange the circles (represented by their equations in general form) in ascending order of their radius lengths. X2 y2 − 2x 2y −
Colt1911 [192]

Circles (represented by their equations in general form) in ascending order of their radius lengths can be arranged as first-fifth-second-forth-third-seventh-sixth.

<h3>What is the equation of circle?</h3>

The equation of the circle is the equation which is used to represent the circle in the algebraic equation form with the value of center point in the coordinate plane and measure of radius.

The standard form of the equation of the circle can be given as,

(x-h)^2+(y-k)^2=r^2

Here (h,k) is the center of the circle and (r) is the radius of the circle.

Lets arrange the first equation, in standard form of equation of circle as,

x^2 +y^2 - 2x+ 2y -1 = 0 \\(x^2 - 2x) +(y^2+ 2y )= 1\\(x^2 - 2x+1) +(y^2+ 2y +1)= 1+1+1\\(x-1)^2+(y+1)^2=(\sqrt{3})^2

The radius of this circle is √(3).

Lets arrange the second equation, in standard form of equation of circle as,

x^2 +y^2 - 4x+ 4y - 10 = 0  \\(x^2 - 4x) +(y^2+ 4y )= 10\\(x^2 - 4x+4) +(y^2+ 4y +4)= 10+4+4\\(x-2)^2+(y+2)^2=(\sqrt{18})^2

The radius of this circle is √(18).

Lets arrange the third equation, in standard form of equation of circle as,

x^2 +y^2 - 8x - 6y - 20 = 0   \\(x^2 - 8x) +(y^2-6y )= 20\\(x^2 - 8x+16) +(y^2- 6y +9)= 10+16+9\\(x-4)^2+(y-3)^2=(\sqrt{45})^2

The radius of this circle is √(45).

Similarly, radius of the forth, fifth, sixth and seventh circle is √(23), √(5), √(117) and √(46) units.

Hence, the circles (represented by their equations in general form) in ascending order of their radius lengths can be arranged as first-fifth-second-forth-third-seventh-sixth.

Learn more about the equation of circle here;

brainly.com/question/1506955

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2 years ago
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