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Ymorist [56]
3 years ago
9

Factor the expression 5x^2+24x-5

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
3 0
5x^2+24x-5 factored is: (5x - 1)(x + 5)
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Mila and Ava play a number game. Mila gives Ava a number and she does three computations:
Lady bird [3.3K]

Answer:

Step-by-step explanation:

(x-5)2+8 = 92

2x-10+8 = 92

2x = 94

x = 47

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A plane intersects both nappes of a double-napped cone but does not go through the vertex of the cone. What conic section is for
lisabon 2012 [21]
<span>When a plane intersects both nappes of a double-napped cone but does not go through the vertex of the cone, the conic section that is formed by the intersection is a curve known as hyperbola. 
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 [(x-h)^2/a^2]-[(y-k)^2/b^2]=1 (Horizontal axis)
 </span>[(y-k)^2/a^2]-[(x-h)^2/b^2]=1 (Vertical axis)<span>
  Therefore, the answer is: Hyperbola.
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Find the area 10yd, 4yd, 10yd, 13yd and 8yd​
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41,600yd's is the area....

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3 years ago
How much fudge will each person get if 7 people share one half of a pound of fudge equally? Ow much fudge will each person get i
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Answer:

B

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What is the positive slope of the asymptote of (y+11)^2/100-(x-6)^2/4=1? The positive slope of the asymptote is .
VladimirAG [237]

Answer:

the  positive slope of the asymptote = 5

Step-by-step explanation:

Given that:

\frac{(y+11)^2}{100} -\frac{(x-6)^2}{4} =1

Using the standard form of the equation:

\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}= 1

where:

(h,k) are the center of the hyperbola.

and the y term is in front of the x term  indicating that the  hyperbola opens up and down.

a = distance that indicates  how far above and below of the center the vertices of the hyperbola are.

For the above standard equation; the equation for the asymptote is:

y = \pm \frac{a}{b} (x-h)+k

where;

\frac{a}{b} is the slope

From above;

(h,k) = 11, 100

a^2 = 100

a = \sqrt{100}

a = 10

b^2 =4

b = \sqrt{4}

b = 2

y = \pm \frac{10}{2} (x-11)+2

y = \pm 5 (x-11)+2

y = 5x-53 , -5x -57

Since we are to find the positive slope of the asymptote: we have  

\frac{a}{b} to be  the slope in the equation  y = \pm \frac{10}{2} (y-11)+2

\frac{a}{b}  = \frac{10}{2}

\frac{a}{b}  = 5

Thus, the  positive slope of the asymptote = 5

8 0
3 years ago
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