Answer:
dC =0.6899T + 30.02
dC/C = (0.6899T + 30.02)/(35.74 + 0.6215T - 35.75V^0.16 + 0.4275Tv^0.16
Step-by-step explanation:
C= 35.74 + 0.6215T - 35.75v^0.16 + 0.4275Tv^0.16
dC = 35.74 + 0.6215T - (35.75×0.16) +:(0.4275×0.16)
dC = 35.74 + 0.6215T - 5.72 + 0.684T
dC = 0.6899T + 30.02
dC/C = (0.6899 + 30.02)/(35.74 + 0.6215T - 35.75Tv^0.16 + 0.4275Tv^0.16
Hello!
This question is an example of composition of functions. It is using range values of some given function as domain values of some other given function to find new range values. Remember that the domain of the composite function will be the same as the domain of the first function.
Given f(g(x)), for f =
, substitute x with g(x) =
.
Therefore,
.
Answer:
Solution of the system will be (-3, 6).
Step-by-step explanation:
If a system of linear equations have been given in the question then we can find the solution of the linear equations by solving these equation algebraically.
But when a graph of the system of equation have been given solution of the system is the point of intersections Or common points lying on both the lines.
From the given graph,
Coordinates of the common point of both the lines is (-3, 6).
Therefore, solution of the system will be (-3, 6).