Question

The square of a number is equal to 10 less than 7 times that number. What are the two possible solutions? Which of the following equations is used in the process of solving this problem?

Answer 1

Solution: Let x be the number. Transform into equation form: x^2 = 10 - 7x. x^2 + 7x - 10 = 0 Factor: (x-5)(x-2)=0; Thus, x = 5 or x = 2. The two possible solution is 5 and 2.  

Answer 2

Answer:

$x^2+7x-10=0$

Step-by-step explanation:

The two possible solutions are 2 and 5. But the equation used in the process of solving and finding this problem, is x^2 + 7x - 10 = 0 or $x^2+7x-10=0$.

Hope I helped :)