Given:
Vertices of a triangular garden:
A(4,2)
B(2,4)
C(6,4)
Scale factor = 0.5
Find the distance between points:
d = √(x2-x1)^2 + (y2-y1)^2
dAB = 2√2
dBC = 4
dCA = 2√2
A similarly shaped garden is to be created using the scale factor, 0.5:
A' = 2√2 / 0.5 = 4√2
B' = 4 / 0.5 = 8
C' = 2√2 / 0.5 = 4√2
Answer: is this an acute im confused
Step-by-step explanation:
Answer:
a) y = 0, y = 4 and y = 5
b) y ⊂ (- ∞, 0) ∪ (0, 4) ∪ (5, ∞)
c) y ⊂ (4,5)
Step-by-step explanation:
Data provided in the question:
function y(t) satisfies the differential equation:
= y⁴ − 9y³ + 20y²
Now,
a) For constant solution
= 0
or
y⁴ − 9y³ + 20y² = 0
or
y² (y² - 9y + 20 ) = 0
or
y²(y² -4y - 5y + 20) = 0
or
y²( y(y - 4) -5(y - 4)) = 0
or
y²(y - 4)(y - 5) = 0
therefore, solutions are
y = 0, y = 4 and y = 5
b) for y increasing
> 0
or
y²(y - 4)(y - 5) > 0
or
y²
y ⊂ (- ∞, 0) ∪ (0, 4) ∪ (5, ∞)
c) for y decreasing
< 0
or
y²(y - 4)(y - 5) > 0
or
y²
y ⊂ (4,5)