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Neko [114]
3 years ago
15

Please help me i really need this grade !

Mathematics
1 answer:
Goshia [24]3 years ago
8 0

Answer:

C. 8

Step-by-step explanation:

still using the equation a^2 = b^2 = c^2

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George has a triangle-shaped garden in his backyard. He drew a model of this garden on a coordinate grid with vertices A(4, 2),
oksian1 [2.3K]
Given:

Vertices of a triangular garden:

A(4,2)
B(2,4)
C(6,4)
Scale factor = 0.5

Find the distance between points:

d = √(x2-x1)^2 + (y2-y1)^2

dAB = 2√2
dBC = 4
dCA = 2√2

A similarly shaped garden is to be created using the scale factor, 0.5:

A' = 2√2 / 0.5 = 4√2
B' = 4 / 0.5 = 8
C' = 2√2 / 0.5 = 4√2 
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3 years ago
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Answer: is this an acute im confused

Step-by-step explanation:

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Which is not an equation of the line that passes through the points (1, 1) and (5, 5)?
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A function y(t) satisfies the differential equation dy dt = y4 − 9y3 + 20y2. (a) What are the constant solutions of the equation
Darya [45]

Answer:

a) y = 0, y = 4 and y = 5

b) y ⊂ (- ∞, 0) ∪ (0, 4) ∪ (5, ∞)

c) y ⊂ (4,5)

Step-by-step explanation:

Data provided in the question:

function y(t) satisfies the differential equation:

\frac{dy}{dt} = y⁴ − 9y³ + 20y²

Now,

a) For constant solution

\frac{dy}{dt} = 0

or

y⁴ − 9y³ + 20y² = 0

or

y² (y² - 9y + 20 ) = 0

or

y²(y² -4y - 5y + 20) = 0

or

y²( y(y - 4) -5(y - 4)) = 0

or

y²(y - 4)(y - 5) = 0

therefore, solutions are

y = 0, y = 4 and y = 5

b) for   y increasing

\frac{dy}{dt} > 0

or

y²(y - 4)(y - 5) > 0

or

y²

y ⊂ (- ∞, 0) ∪ (0, 4) ∪ (5, ∞)

c) for   y decreasing

\frac{dy}{dt} < 0

or

y²(y - 4)(y - 5) > 0

or

y²

y ⊂ (4,5)

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hodyreva [135]

Answer is A yup I'm sure

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