Answer:
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Step-by-step explanation:
The standard form of a quadratic equation is

, while the vertex form is:

, where (h, k) is the vertex of the parabola.
What we want is to write

as

First, we note that all the three terms have a factor of 3, so we factorize it and write:

.
Second, we notice that

are the terms produced by

, without the 9. So we can write:

, and substituting in

we have:
![\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11]](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%20y%3D3%28x%5E2-6x-2%29%3D3%5B%28x-3%29%5E2-9-2%5D%3D3%5B%28x-3%29%5E2-11%5D)
.
Finally, distributing 3 over the two terms in the brackets we have:
![y=3[x-3]^2-33](https://tex.z-dn.net/?f=y%3D3%5Bx-3%5D%5E2-33)
.
Answer:
Answer:
B. 3.6
Step-by-step explanation:
I have no idea if this is right but my logic is 3.6 - 3.6 = 0
Answer:
1) 2
2) -7/6
3) -5/4
4) -1/2
5) -13/28
6) 9/7
Step-by-step explanation:
5) (-6-7)/(17-(-11))=-13/28
6) (4-(-5)/(3-(-4))=9/7