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2 years ago

Find the gradient of the line segment between the points (2,3) and (4,7)

Mathematics

1 answer:

belka [17]2 years ago

5 0

Answer:

Step-by-step explanation:

The gradient or slope of a straight line which is found between two points (x1, y1) and (x2, y2) is given by the formula:

m = (y2 - y1) / (x2 - x1)

Where y2 = 7

y1 = 3

x2 = 4

x1 = 2

=> m = (7 - 3) / (4 - 2)

m = 4 / 2 = 2

The gradient is 2.

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The product of a rational number

kati45 [8]

Answer:

I think it's true. hope this helps!!

6 0

3 years ago

Need help fast thanks and god bless

Nuetrik [128]

Answer:

275.

Step-by-step explanation:

The gradient of the graph is 70/2 = 35 and it passes through the origin so we can write its equation as

y = 35x.

The gradient of the function represented by the the table is

(240-180) / (4-3) = 60

Ehen x = 3 y = 180 so when x = 0 y = 180 - 60 - 60 - 60 = 0 and the equation of this function is

y = 60x.

For the first equation when x = 11, y = 35*11 = 385.

For the second it is 60 * 11 = 660

So our answer is 660 - 385

= 275

7 0

2 years ago

The figure below shows a large block of cheese. Cheese Block 10 inches 4 inches 6 inches What is the volume of the block of chee

Masja [62]

Answer:120 cubic inches

Step-by-step explanation:

(4*10)*6 (40*6)/2 240/2=120 cubic inches

8 0

2 years ago

Answers? & provide how u did it if u can thank u.

sp2606 [1]

Answer:

Step-by-step explanation:

a² = 10² - 6²

a² = 100 - 36

a² = 64

a = √64

a = 8

So, the value of a is 8

Hope this is helpful and useful :)

7 0

3 years ago

Read 2 more answers

The time t required to drive a certain distance varies inversely with the speed r. if it takes 4 hours to drive the distance at

Aleksandr [31]

$\bf \qquad \qquad \textit{inverse proportional variation}
\\\\
\textit{\underline{y} varies inversely with \underline{x}}\qquad \qquad y=\cfrac{k}{x}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------$

$\bf \stackrel{\textit{time \underline{t} required to drive a certain distance varies inversely with the speed \underline{r}}}{t=\cfrac{k}{r}}
\\\\\\
\textit{we also know that }
\begin{cases}
t=4\\
r=35
\end{cases}\implies 4=\cfrac{k}{35}\implies 4(35)=k
\\\\\\
140=k\qquad therefore\qquad \boxed{t=\cfrac{140}{r}}
\\\\\\
\textit{now, when \underline{r} = 45, what is \underline{t}?}\qquad t=\cfrac{140}{45}$

4 0

2 years ago