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Tema [17]
3 years ago
6

Which of the following answers describe how to calculate the acceleration of an object?

Physics
2 answers:
Blababa [14]3 years ago
7 0

A. Divide the change in the objects velocity by the time it takes to make that change.

Explanation:

Acceleration is a vector quantity whose magnitude is given by the following equation:

a=\frac{\Delta v}{\Delta t}

where

\Delta v is the change in velocity of the object

\Delta t is the time it took to make the change in velocity

Therefore, we see that this equation corresponds to choice A.

Olin [163]3 years ago
6 0
I think it's A I hope this is right but I just studied this so I think this is the right answer
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Sever21 [200]
The answer would be phosphorus
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4 years ago
Explain what you think is happening in this picture
Dima020 [189]

Answer:

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Explanation:

5 0
3 years ago
A piece of warm concrete is placed in a cold-water tank, and energy flows between the concrete and the water. Which way does the
sammy [17]

Answer:

Heat flows from hot to cold objects. When a hot and a cold body are in thermal contact, they exchange heat energy until they reach thermal equilibrium, with the hot body cooling down and the cold body warming up. This is a natural phenomenon we experience all the time.

Explanation:

3 0
2 years ago
An insulated lamp bulb is on the bottom of a swimming pool at a point 2.5 m from a wall; the pool is 2.5 m deep and filled to th
pashok25 [27]

Answer:

option A

Explanation:

given,

lamp position from pool wall = 2.5 m

height of the pool = 2.5 m

now,

tan \theta = \dfrac{P}{B}

\theta =tan^{-1}(\dfrac{2.5}{2.5})

\theta =45^0

from the triangle

θ = i = 45°

using Snell's law

n₁ sin i = n₂ sin r

n₁ =4/3     n₂ = 1  

now,

\dfrac{sin r}{sin i}=\dfrac{n_1}{n_2}

\dfrac{sin r}{sin 45^0}=\dfrac{\dfrac{4}{3}}{1}

sin r=\dfrac{1}{\sqrt{2}}\times \dfrac{4}{3}

r = sin⁻¹(0.9428)

r = 70.5°

hence, the correct answer is option A

8 0
3 years ago
Air is warmed and moisten as it moves through both the mouth and nasal passages.
Alexxx [7]

Well, in my own personal case, I can actually move the air in either
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When I move the air inward from the outside, it's warmed and moistened.

When I move it outward from the inside, it's not.
3 0
3 years ago
Read 2 more answers
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