A football player at practice pushes a 60 kg blocking sled across the field at a constant speed. The coefficient of kinetic fric
1 answer:
Answer:
C. 180 N
Explanation:
= mass of the blocking sled = 60 kg
= Coefficient of kinetic friction = 0.30
= kinetic frictional force acting on the sled
kinetic frictional force acting on the sled is given as
=Force applied
For the sled to move at constant speed, the applied force must be same as the frictional force
You might be interested in
Answer:
E = 2k
Explanation:
Gauss's law states that the electric flux equals the wax charge between the dielectric permeability.
We must define a Gaussian surface that takes advantage of the symmetry of the problem, let's use a cylinder with the faces perpendicular to the line of charge. Therefore the angle between the cylinder side area has the same direction of the electric field which is radial.
Ф = ∫ E . dA = E ∫ dA = q_{int} /ε₀
tells us that the linear charge density is
λ = q_ {int} /l
q_ {int} = l λ
we substitute
E A = l λ /ε₀
is area of cylinder is
A = 2π r l
we substitute
E =
E =
the amount
k = 1 / 4πε₀
E = 2k