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r-ruslan [8.4K]
3 years ago
11

Please help! Add using a number line −2/5 +4/5 = ?

Mathematics
1 answer:
kobusy [5.1K]3 years ago
5 0

-  \frac{2}{5}  +  \frac{4}{5}  =  \frac{2}{5}
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Someone please help me. Asap ?
sergejj [24]

Answer:

Graph A

Step-by-step explanation:

A directly proportional relationship must create a straight line that goes through the origin (0,0) ( note that the slope can be negative or positive in a proportional relationship. )

All graphs show a straight line going through the origin except Graph A.

Graph A shows a straight line however that line does not go through the origin therefore it is not a proportional relationship

7 0
3 years ago
Find the surface area of this prism.<br> Round to the nearest tenth.
avanturin [10]

Answer:

The answer is 493.3

Step-by-step explanation:

6.72 x 12.7 x 5.78 = 493.28872

And 493.28872 rounded to the nearest tenth is 493.3 because the original number in the tenth place is 2 and then the digit before that is 8 which in this case is your rounding digit. Round up If the number is greater than 5 and round down if its less than 5. In this case its greater than 5 to that leaves you with 28 so now you have 493.28, 28 rounded to the nearest tenth is 30 and just take the 0 away, as if it didn't exist.

4 0
3 years ago
Read 2 more answers
A race car can reach a speed of 185 miles per hour. How fast is that in feet per second?
snow_lady [41]
The car can go exactly 271.3333333333333 feet per second. you are welcome.
3 0
3 years ago
Please help :c <br><br> the first word is find
xeze [42]

Answer:

The values of r_{2} and \alpha_{2} are 2 and 150º.

Step-by-step explanation:

The complete statement is:

<em>Find </em>\alpha_{2}<em> and </em>r_{2}<em> such that  </em>\sin \theta - \sqrt{3}\cdot \cos \theta = r_{2}\cdot \cos (\theta - \alpha_{2})<em>. </em>

We proceed to use the following trigonometric identity:

\cos (\theta - \alpha_{2}) = \cos \theta \cdot \cos \alpha_{2} +\sin \theta \cdot \sin \alpha_{2} (1)

\sin \theta -\sqrt{3}\cdot \cos \theta = r_{2}\cdot \cos \theta \cdot \cos \alpha_{2}+r_{2}\cdot \sin \theta \cdot \sin \alpha_{2}

By direct comparison we derive these expressions:

r_{2}\cdot \sin \alpha_{2} = 1 (2)

r_{2}\cdot \cos \alpha_{2} = -\sqrt{3} (3)

By dividing (2) by (3), we have the following formula:

\tan \alpha_{2} = -\frac{1}{\sqrt{3}}

\tan \alpha_{2} = -\frac{\sqrt{3}}{3}

The tangent function is negative at second and fourth quadrants. That is:

\alpha_{2} = \tan^{-1} \left(-\frac{\sqrt{3}}{3} \right)

There are at least two solutions:

\alpha_{2,1} = 150^{\circ}, \alpha_{2,2} = 330^{\circ}

And the value of r_{2}:

r_{2}^{2}\cdot \sin^{2}\alpha_{2} + r_{2}^{2}\cdot \cos^{2}\alpha_{2} = 4

r_{2}^{2} = 4

r_{2} = 2

The values of r_{2} and \alpha_{2} are 2 and 150º.

5 0
3 years ago
-x + 8x= -21 find what x is
Reptile [31]

Answer:

-3

Step-by-step explanation:

-x+8x=-21

7x=-21

7x/7=-21/7

x=-3

6 0
3 years ago
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