(x+1)² + (y-1)²=64
(x+1)² + <u>(y-1)²</u>=<em>8²</em>
(x-h)² +<u> (y-k)²</u> = <em>r²</em>
center of the circle (-1,1), r=8.
The intersection of lines y=-14x+3 and y=-32x+3 is (0, 3)
<h3>How to determine the intersection of the lines?</h3>
The lines are given as:
y = -14x + 3 and y = -32x+3
Substitute y = -32x+3 in
-32x+3 = -14x + 3
Evaluate the like terms
-18x = 0
Divide by -18
x = 0
Substitute x = 0 in y = -14x + 3
y = -14(0) + 3
Evaluate
y = 3
Hence, the intersection of lines y=-14x+3 and y=-32x+3 is (0, 3)
Read more about linear equations at:
brainly.com/question/14323743
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The answer is not applicable. theres not enough information. -fvmousskaylaa
84+92+87+104=367
500-367=133
He needs to plant 133 shrubs on Friday
Do you have a photo of the picture?