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abruzzese [7]
3 years ago
11

Dose anyone have the answer to this question

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
7 0

Answer: (A) SAS  (B) No  (C) SSS  (D) No

<u>Step-by-step explanation:</u>

A) ET ≅ MT, ∠T ≅ ∠T, TA ≅ TA  ⇒  Side-Angle-Side

B) top and base are congruent, diagonal is congruent to itself, but there is no way to prove that two angles are congruent without knowing if either of the sides are parallel.

C) JU ≅ JE, UN ≅ EN, JN ≅ JN ⇒ Side-Side-Side

D) angle-angle-angle only proves similarity, not congruency

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Complete the table and sketch the graph​
Simora [160]

Answer:

where's the picture?

Step-by-step explanation:

can I have the pic po

4 0
2 years ago
Find the arc-length parametrization of the curve that is the intersection of the elliptic cylinder x 2 + y 2/2 = 1 and the plane
storchak [24]

Answer:

f(\theta) = (cos(\frac{\theta}{\sqrt2}), \sqrt2 sin(\frac{\theta}{\sqrt2}), cos(\frac{\theta}{\sqrt2})-2)

0 ≤ Ф ≤ 4π.

Step-by-step explanation:

since x²+y²/2 = 1, then x²+s² = 1, with s = (y/√2)². Hence, (x,s) = (cos(Ф),sin(Ф)) and (x,y,z) = (cos(Ф),√2 sin(Ф), cos(Ф)-2). This expression evaluated in zero gives as result (1,0,-1). The derivate of this function is (-sin(Ф),√2 cos(Ф), -sen(Ф))

the norm of the derivate is √(sin²(Ф) + 2cos²(Ф)+sin²(Ф)) = √2. In order to make the norm equal to 1, i will divide Ф by √2, so that a √2 is dividing each term after derivating.

We take

f(\theta) = (cos(\frac{\theta}{\sqrt2}), \sqrt2 sin(\frac{\theta}{\sqrt2}), cos(\frac{\theta}{\sqrt2})-2)

Note that

  • f(0) = (1,0,-1)
  • f'(\theta) = (\frac{sin(\frac{\theta}{\sqrt2})}{\sqrt2}, cos(\frac{\theta}{\sqrt2})}, \frac{sin(\frac{\theta}{\sqrt2})}{\sqrt2})

Whose square norm is 1/2cos²(Ф/2)+sen²(Ф/2)+1/2cos²(Ф/2) = 1. This is te parametrization that we wanted.

The values from Ф range between 0 an 4π, because the argument of the sin and cos is Ф/2, not Ф, Ф/2 should range between 0 and 2π.

6 0
3 years ago
Please help
daser333 [38]

Answer:

See Below.

Step-by-step explanation:

We can write a two-column proof.

<u>Statements:</u>                                                <u>Reasons: </u>

<u></u>\displaystyle 1)\, F\text{ is the midpoint of } AE                           Given

\displaystyle 2) \, \overline{FA} \cong \overline{FE}                                                  Definition of Midpoint

\displaystyle 3) \, AB\parallel DE                                                   Given

\displaystyle 4)\, \angle B \cong \angle D                                                  Alt. Int. Angles Are Congruent  

\displaystyle 5)\, \angle A \cong E                                                     Alt. Int. Angles Are Congruent      

\displaystyle 6) \, \Delta BFA \cong \Delta DFE                                      AAS Congruence

6 0
2 years ago
Enrique collects miniature cars. He has one large case that holds 20 cars and 3 same-size, smaller cases to hold his cars.
dedylja [7]

Answer:

  • C = 3n + 20

Step-by-step explanation:

There is one large case with 20 cars and 3 small cases with n cars in each.

<u>Possible number of cars C is:</u>

  • C = 3n + 20
3 0
2 years ago
Square ABCD has side length a. Half circles with
Inga [223]

The area of the shaded region is 0.215a^2

<h2>Area of composite objects</h2>

The area of the shaded region is expressed according to the formula:

  • A = A_s - A_c

Get the area of the square As

As = a²

A_c = \pi (0.5a)^2\\&#10;A_c = 0.785a^2

Take the difference in the areas

Area of the shaded part = a^2-0.785a^2\\&#10;

Area of the shaded part = 0.215a^2

Hence the area of the shaded region is 0.215a^2

Learn more on area of composite objects here: brainly.com/question/22716761

7 0
2 years ago
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