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2 years ago

15

Risa is sewing a ribbon around the sides of a square blanket. Each side of the blanket is 72 inches long, how many inches of the

ribbon will risa need?

1 answer:

vaieri [72.5K]2 years ago

5 0

72*4=288in of ribbon

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Washington Middle School sold 405 tickets to the annual musical production for Friday night. If the tickets sold for Friday nigh

Effectus [21]

Answer

900

Step-by-step explanation:

45% of 900= 405

(hope this helps :)!!

4 0

2 years ago

Read 2 more answers

Find the inverse of the function f(x)=−4x2−8, x≤0.

xxTIMURxx [149]

$\sqrt{ \frac{x+8}{-4} }$

You get this by switching the f(x) and the x and then solving for the new f(x)

6 0

2 years ago

A long novel is opened to a random page; the probability that the page is numbered something between 21 and 31.

Harrizon [31]

Using the uniform distribution, considering that the novel has 435 pages, the probability that the page is numbered something between 21 and 31 is:

$p = \frac{10}{435}$

<h3>What is the uniform probability distribution?</h3>

It is a distribution with two bounds, a and b, in which each outcome is equally as likely.

The probability of finding a value between c and d is:

$P(c \leq X \leq d) = \frac{d - c}{b - a}$

Researching the problem on the internet, it is found that the novel has 435 pages, hence a = 0, b = 435, and the probability that the page is numbered something between 21 and 31 is given by:

$P(21 \leq X \leq 31) = \frac{31 - 21}{435 - 0} = \frac{10}{435}$

More can be learned about the uniform distribution at brainly.com/question/13889040

#SPJ1

5 0

2 years ago

Solve the system of equations by finding the reduced row echelon form of the augmented matrix. Write the solutions for x and y i

Gwar [14]

Answer:

The solutions for the given system of equations are:

$\left \{ {{x=-5} \atop {y=12-4z}} \right.$

Step-by-step explanation:

Given the equation system:

$\left \{ {{3x+y+4z=-3} \atop {-x+y+4z=17}} \right.$

We obtain the following matrix:

$\left[\begin{array}{cccc}3&1&4&-3\\-1&1&4&17\end{array}\right]$

<u>Step 1:</u> Multiply the fisrt row by 1/3.

$\left[\begin{array}{cccc}1&\frac{1}{3} &\frac{4}{3}&-1\\-1&1&4&17\end{array}\right]$

<u>Step 2:</u> Sum the first row and the second row.

$\left[\begin{array}{cccc}1&\frac{1}{3} &\frac{4}{3}&-1\\0&\frac{4}{3} &\frac{16}{3}&16\end{array}\right]$

<u>Step 3:</u> Multiply the second row by 3/4.

$\left[\begin{array}{cccc}1&\frac{1}{3} &\frac{4}{3}&-1\\0&1 &4&12\end{array}\right]$

<u>Step 4:</u> Multiply the second row by -1/3 and sum the the first row.

$\left[\begin{array}{cccc}1&0 &0&-5\\0&1 &4&12\end{array}\right]$

The result of the reduced matrix is:

$\left \{ {{x=-5} \atop {y+4z=12}} \right.$

This is equal to:

$\left \{ {{x=-5} \atop {y=12-4z}} \right.$

These are the solutions for the system of equations in terms of z, where z can be any number.

6 0

2 years ago

Find 3 consecutive odd integers such that 10 times the first is 59 more than the third?

Nikolay [14]

Answer: The required three consecutive odd integers are 7, 9 , 11.

Step-by-step explanation:

Let x , x+2 , x+4 be the three consecutive odd integers.

As per given ,

10(x) = 59+x+4

⇒10x= 59+x+4

⇒ 9x= 63

⇒ x= 7 [ divide both sides by 7]

Hence, the required three consecutive odd integers are 7, 9 , 11.

7 0

2 years ago