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3 years ago

How does sound intensity differ from loudness?

1 answer:

3 0

Loudness refers to how loud or soft a sound seems to a listener. The loudness of sound is determined, in turn, by the intensity, or amount of energy, in sound waves. The unit of intensity is the decibel (dB). As decibel levels get higher, sound waves have greater intensity and sounds are louder.

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Two children stretch a jump rope between them and send wave pulses back and forth on it. The rope is 3.3 m long, its mass is 0.5

EastWind [94]

Answer:

The linear mass density of rope is 0.16 kg/m.

Explanation:

mass, m = 0.52 kg

force, F = 47 N

length, L = 3.3 m

(a) The linear mass density of the rope is defined as the mass of the rope per unit length.

Linear mass density = m/L = 0.52/3.3 = 0.16 kg/m

7 0

3 years ago

The Bohr model of the hydrogen atom pictures the electron as a tiny particle moving in a circular orbit about a stationary proto

igor_vitrenko [27]

a) The angular velocity of the electron is $4.12\cdot 10^{16} rad/s$

b) The number of revolutions per second is $6.54\cdot 10^{15}$ rev/s

c) The centripetal acceleration of the electron is $8.98\cdot 10^{22} m/s^2$

Explanation:

This is a problem of uniform circular motion: in fact, the electron orbits around the proton in a uniform circular motion.

The angular velocity of an object in uniform circular motion is given by

$\omega = \frac{v}{r}$

where

v is the linear speed

r is the radius of the trajectory

For the electron orbiting around the proton, we have

$v=2.18 \cdot 10^6 m/s$

$r=5.29\cdot 10^{-11} m$

Therefore, the angular velocity is

$\omega=\frac{2.18\cdot 10^6}{5.29\cdot 10^{-11}}=4.12\cdot 10^{16} rad/s$

The period of revolution of the electron is given by

$T=\frac{2\pi}{\omega}$

where

$\omega = 4.12\cdot 10^{16}rad/s$ is the angular velocity

Substituting,

$T=\frac{2\pi}{4.12\cdot 10^{16}}=1.53\cdot 10^{-16}s$

The period is the time the electron takes to make one complete orbit around the proton; therefore, the number of revolutions of the electrons in one second is:

$f=\frac{1}{T}=\frac{1}{1.53\cdot 10^{-16}}=6.54\cdot 10^{15}$ rev/s

The centripetal acceleration of an object in circular motion is

$a=\frac{v^2}{r}$

where

v is the linear speed

r is the radius of the circle

For the electron, we have

$v=2.18 \cdot 10^6 m/s$

$r=5.29\cdot 10^{-11} m$

Therefore, the centripetal acceleration is

$a=\frac{(2.18\cdot 10^6)^2}{5.29\cdot 10^{-11}}=8.98\cdot 10^{22} m/s^2$

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

7 0

4 years ago

Give three advantages and three disadvantages of nuclear power. Support each with evidence. This response should be a complete a

Talja [164]

The paragraph is going to be your responsibility but I can provide the pros and cons.

Advantages include the fact that Uranium is a plentiful resource, it is relatively clean, and it takes very little resources to make power.

However disadvantages include radioactive byproducts which need longtime storage. Uranium is also a nonrenewable resource, meaning it can run out. Additionally safety issues regarding melt downs are a major concern.

4 0

3 years ago

The number of planets, besides the earth, that are visible to the unaided eye is

sergejj [24]

The answer should be 5 it’s easy

3 0

3 years ago

4. A truck with a mass of 6,500 Kg can exert a force of 29,250 N when stopping. What is the deceleration

Vitek1552 [10]

Deceleration = 29250 / 6500 = 4.5 m/s^2

7 0

4 years ago