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Alex17521 [72]
3 years ago
10

How does sound intensity differ from loudness?

Physics
1 answer:
Alchen [17]3 years ago
3 0
Loudness<span> refers to how loud or soft a </span>sound<span> seems to a listener. The </span>loudness<span> of </span>sound is<span> determined, in turn, by the </span>intensity<span>, or amount of energy, in </span>sound<span> waves. The unit of </span>intensity is<span> the decibel (dB). As decibel levels get higher, </span>sound<span> waves have greater </span>intensity<span> and </span>sounds are<span> louder.</span>
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Consider two parallel plate capacitors. The plates on Capacitor B have half the area as the plates on Capacitor A, and the plate
vichka [17]

Answer:

CB = 4.45 x 10⁻⁹ F = 4.45 nF

Explanation:

The capacitance of a parallel plate capacitor is given by the following formula:

C = ε₀A/d

where,

C = Capacitance

ε₀ = Permeability of free space

A = Area of plates

d = Distance between plates

FOR CAPACITOR A:

C = CA = 17.8 nF = 17.8 x 10⁻⁹ F

A = A₁

d = d₁

Therefore,

CA = ε₀A₁/d₁ = 17.8 x 10⁻⁹ F   ----------------- equation 1

FOR CAPACITOR B:

C = CB = ?

A = A₁/2

d = 2 d₁

Therefore,

CB = ε₀(A₁/2)/2d₁

CB = (1/4)(ε₀A₁/d₁)

using equation 1:

CB = (1/4)(17.8 X 10⁻⁹ F)

<u>CB = 4.45 x 10⁻⁹ F = 4.45 nF</u>

5 0
3 years ago
A football player runs directly down the field for 45m before turning to the right at an angle of 25 degrees from his original d
Fiesta28 [93]

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5 0
3 years ago
A world-class tennis player can serve a tennis ball at 150 mi/h (about 67 m/s). The length of a tennis
Rudik [331]

Answer:

The expression for the time taken by an object to move with a speed at some distance is,

t=<u> </u><u>d</u><u>/</u><u>v</u>

Here, t is the time taken by the opponent to react, d is the length of the court, andis the speed of the ball.

Explanation:

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3 years ago
7. A stream of water strikes a stationary turbine blade horizontally, as the drawing illustrates. The oncoming water stream has
NNADVOKAT [17]

Answer:

The magnitude of the average force exerted on the water by the blade is 960 N.

Explanation:

Given that,

The mass of water per second that strikes the blade is, \dfrac{m}{t}=30\ kg/s

Initial speed of the oncoming stream, u = 16 m/s

Final speed of the outgoing water stream, v = -16 m/s

We need to find the magnitude of the average force exerted on the water by the blade. It can be calculated using second law of motion as :

F=\dfrac{\Delta P}{\Delta t}

F=\dfrac{m(v-u)}{\Delta t}

F=30\ kg/s\times (-16-16)\ m/s

F = -960 N

So, the magnitude of the average force exerted on the water by the blade is 960 N. Hence, this is the required solution.

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4 years ago
Write a short story, the story is to describe a motion activity appropriate for school that contains 2 acceleration segments. Th
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