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Alex17521 [72]
3 years ago
10

How does sound intensity differ from loudness?

Physics
1 answer:
Alchen [17]3 years ago
3 0
Loudness<span> refers to how loud or soft a </span>sound<span> seems to a listener. The </span>loudness<span> of </span>sound is<span> determined, in turn, by the </span>intensity<span>, or amount of energy, in </span>sound<span> waves. The unit of </span>intensity is<span> the decibel (dB). As decibel levels get higher, </span>sound<span> waves have greater </span>intensity<span> and </span>sounds are<span> louder.</span>
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A force of 200 N is applied at piston A, which has a surface area of 4
stira [4]

Answer:

60 cm²

Explanation:

Pressure = Force / Surface area

This is a 2 stage problem which requires working out pressure of piston A and then using that pressure from piston A to calculate the surface area of piston B

Firstly work out pressure of Piston A:

Pressure = 200 / 4

Pressure = 50 N/cm²

Then work out the Surface area of piston B :

Since the pressure is transferred the pressure stays the same so :

Surface area = Force / Pressure

Surface area = 3000 / 50

Surface area = 60 cm²

7 0
4 years ago
two protons are released from rest when they are 0.750 nm apart (a)what is the maximum speed they will reach ? when does this sp
Keith_Richards [23]

Answer:

And so calculating we get the maximum speed at each proton will reach To be 1.36 Times 10 to the four m the second

8 0
2 years ago
Which best explains the direction of the moving force of air?. . A.. from warm temperatures to cold temperatures. . B.. from are
borishaifa [10]
Out of the choices given, the best choice to explain the direction of the moving force of air is from area o high pressure to areas of low pressure. The correct answer is B. 
8 0
3 years ago
Read 2 more answers
Explain the relationship between the distance between the string and your elbow and the effort required to lift the mass.
MissTica

Answer:

Sorry I I’m a little lost

Explanation:

5 0
3 years ago
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A long, thin solenoid has 390 turns per meter and a radius of 1.20 cm. The current in the solenoid is increasing at a uniform ra
gtnhenbr [62]

To solve this problem it is necessary to apply the concepts related to Faraday's law and the induced emf.

By definition the induced electromotive force is defined as

\int E dl = -\frac{d\phi}{dt}

\int E dl = -(\frac{dB}{dt})A

Where,

\phi = Electric field

B = Magnetic Field

A = Area

At the theory the magnetic field is defined as,

B = \mu_0 NI

Where,

N = Number of loops

I = current

\mu_0 = Permeability constant

We know also that the cross sectional area, is the area from a circle, and the length is equal to the perimeter then

A = \pi r^2

l = 2\pi r

Replacing at the previous equation we have that

E (2\pi r) = \mu_0 n (\frac{di}{dt})(\pi R^2)

Where,

R = Radius of the solenoid

r = The distance from the axis

Re-arrange to find the current in function of time,

\frac{di}{dt} = \frac{Er}{\mu_0 NR^2}

Replacing our values we have

\frac{di}{dt} = \frac{(8.00*10^{-6})(0.0348)}{(4\pi*10^{-7})(390)(1.2*10^-2)^2}

\frac{di}{dt} = 3.94487A/s

8 0
3 years ago
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