How did you manage to overcome the difficulties that arose?
1 answer:
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Answer:
4.6 m
Explanation:
First of all, we can find the frequency of the wave in the string with the formula:
where we have
L = 2.00 m is the length of the string
T = 160.00 N is the tension
is the mass linear density
Solving the equation,
The frequency of the wave in the string is transmitted into the tube, which oscillates resonating at same frequency.
The n=1 mode (fundamental frequency) of an open-open tube is given by
where
v = 343 m/s is the speed of sound
Using f = 37.3 Hz and re-arranging the equation, we find L, the length of the tube:
Answer:
A) the ammeter is x
B)
- voltage across R₁ (left resistor) = 0.75 V
- voltage across the right one = 0.3 V
C) 1.05 V
Explanation:
From the diagram attached below;
A) Assuming the homes were wired in series, and one of the homes face short circuit then all the houses would face power cut but it doesn't happen. So they must be connected in parallel.
Therefore; The ammeter is connected in series, Hence, the ammeter is x and the voltmeter must be z.
B)
Given that:
x = 0.15 A
z = 0.3 V
Resistor (R) on the left = 5 ohms
Then, voltage across R₁ (left resistor) = 5×(x)
= 5×0.15
= 0.75 V
voltage across the right one = z = 0.3 V
C)
The total voltage of battery = 0.75+0.3 = 1.05 V
