Answer: B and D
Step-by-step explanation:
First, solve the terms inside of the parenthesis. As a general rule, whenever you multiply two terms that have the same base, you can add their exponents.
Applying this rule, the base in the problem is 6, and the exponents are 3 and -4. The sum of 3 and -4 leaves -1. Therefore, this is one of our solutions:

When you have an exponential term raised to another exponent, you can simply multiply the exponents. In the previous solution given above, multiply -1 and -3 to get 3. Therefore our second solution is:

Answer:
12
Step-by-step explanation:
Step-by-step explanation:
-1/3 a + 4 ≤ 0
3*(-1/3a) + 4*3 ≤ 0*3
-a + 12 ≤ 0
12 ≤ a
12 ⩾a
a⩾12
Answer:
Kindly check explanation
Step-by-step explanation:
Given :
Sample size, n = 30
Tcritical value = 2.045
Null hypothesis :
H0: μ = 9.08
Alternative hypothesis :
H1: μ≠ 9.08
Sample mean, m = 8.25
Samole standard deviation, s = 1.67
Test statistic : (m - μ) ÷ s/sqrt(n)
Test statistic : (8.25 - 9.08) ÷ 1.67/sqrt(30)
Test statistic : - 0.83 ÷ 0.3048988
Test statistic : - 2.722
Tstatistic = - 2.722
Decision region :
Reject Null ; if
Tstatistic < Tcritical
Tcritical : - 2.045
-2.722 < - 2.045 ; We reject the Null
Using the α - level (confidence interval) 0.05
The Pvalue for the data from Tstatistic calculator:
df = n - 1 =. 30 - 1 = 29
Pvalue = 0.0108
Reject H0 if :
Pvalue < α
0.0108 < 0.05 ; Hence, we reject the Null