consider the line shown on the graph. enter the equation of the line in the form y=mx where m is the slope.

What is the answer and solution steps I’ll give you brainlist and points

BlackZzzverrR [31]

Answer:

the answer is b(-7/4)

Step-by-step explanation:

2(x+5)-3=(2x=1)+1

2x+10-3=-(2x+1)+1

2x+7=-(2x+1)+1

2x+7-2x-1+1

2x+7=2x

2x+7-7+2x-7

x=-7/4

8 0

3 years ago

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1) Find the inverse function of f(x)=1/2x+3

dexar [7]

y = 1/2x + 3
change x and y

x = 1/2y + 3
now find the value of y and that is inverse function

x - 3 =1/2 y
y = 2x- 6

f-(x) = 2x - 6
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for both domain : ( - ∞ , + ∞ )

range f (x) : ( - ∞ , + ∞ ) - { 0 }
range f-(x) :( -∞ , +∞)

8 0

3 years ago

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There are 4 white and 8 red roses in a bouquet. Find the ratios.

kramer

Answer:

1a) 1:2

1b) 2:3

Step-by-step explanation:

1a) 4:8 = 1:2

1b) 4 white and 8 red means 12 total so ratio for red would be 2:3

3 0

4 years ago

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What is the standard equation of the circle in the graph

ivanzaharov [21]

Answer:

option 1

Step-by-step explanation:

formula:(x-h)^(2)*(y-k)^(2)=r^2

well if you move the circle 3 units left h is (-3), plug it in, you get 3, so it is (x+3)^2*(y-k)^(2)=r^2

if you move the circle 2 units up, plug it in you get (-2), so it is

(x+3)^2*(y-2)^(2)=r^2

now, the radius is 3 (we can see from the graph) so radius ^2 is 9, thus

(x+3)^2*(y-2)^(2)=9

this is the answer, and the option that has it is answer is option 1

6 0

3 years ago

The figure is made up of a cylinder and a hemisphere. To the nearest whole number, what is the approximate volume of this figure

Novosadov [1.4K]

Hello!

The figure is made up of a cylinder and a hemisphere. To the nearest whole number, what is the approximate volume of this figure?

Use 3.14 to approximate π .

Enter your answer in the box. in.³

Data: (Cylinder)

h (height) = 7 in

r (radius) = 2.5 in (The diameter is 5 being twice the radius)

Adopting: $\pi \approx 3.14$

V (volume) = ?

Solving: (Cylinder volume)

$V = \pi *r^2*h$

$V = 3.14 *2.5^2*7$

$V = 3.14*6.25*7$

$V = 137.375 \to \boxed{V_{cylinder} \approx 137.38\:in^3}$

Note: Now, let's find the volume of a hemisphere.

Data: (hemisphere volume)

V (volume) = ?

r (radius) = 2.5 in (The diameter is 5 being twice the radius)

Adopting: $\pi \approx 3.14$

If: We know that the volume of a sphere is $V = 4* \pi * \dfrac{r^3}{3}$ , but we have a hemisphere, so the formula will be half the volume of the hemisphere $V = \dfrac{1}{2}* 4* \pi * \dfrac{r^3}{3} \to \boxed{V = 2* \pi * \dfrac{r^3}{3}}$