Answer:
0.204.
Explanation:
- For the following reaction:
<em>CO(g) + Cl₂(g) ⇌ COCl₂(g), </em>
Kp = (P of COCl₂)/(P of CO)(P of Cl₂)
P of COCl₂ = 0.22 atm, P of CO = 0.83 atm, P of Cl₂ = 1.3 atm.
∴ Kp = (P of COCl₂)/(P of CO)(P of Cl₂) = (0.22 atm)/(0.83 atm)(1.3 atm) = 0.204.
Answer:
Francium (Fr)
Explanation:
From the given choices, francium will have the lowest ionization energy.
Ionization energy is the energy required to remove the most loosely held electron within an atom.
The magnitude of the ionization energy depends on the characteristics of the atom in relation to its nuclear charge, atomic radius, stability etc.
- Generally on the periodic table, ionization energy increases from left to right on the table
- As you go from metals to non-metals and to gases, the value of the ionization energy increases steadily.
- Down the group, the value reduces.
- Since Francium is the most metallic of all the given choices, it has the highest ionization energy.
A. It absorbs energy.
reactants are located on the left side of the equation, meaning energy among with other reactants were needed to get the reaction going, so it absorbed energy, which is also the endothermic process. The opposite of that would be having energy on the right side with the products which means that the reaction would've released energy which is the exothermic process. Hope this helps!
The question is incomplete. Complete question is attached below.
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Correct Answer: Option D i.e. 34.8 gReason:
Molecular weight of HgS = 232.66 g/mol
Atomic weight of Hg = 200.59 g/mol
Thus, 200.59 g Hg ≡ 232.66 g of HgS
Therefore, 30 g of Hg ≡
= 34.8 g
Thus,
34.8 g HgS would contain 30 g mass percent of Hg