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2 years ago

What does Gibbs free energy predict?

Chemistry

1 answer:

7nadin3 [17]2 years ago

5 0

Answer:

D. It predicts whether or not a reaction will be spontaneous.

Explanation:

What does Gibbs free energy (ΔG) predict? .

A. It predicts what the rate of the reaction will be. NO. ΔG is a thermodynamical parameter and it is not related to the kinetics of the reaction.

B. It predicts how high the activation energy is. NO. ΔG is a thermodynamical parameter and it is not related to the kinetics of the reaction.

C. It predicts if entropy will increase or decrease. NO. ΔG depends on the entropy but not the other way around.

D. It predicts whether or not a reaction will be spontaneous. YES. If ΔG < 0 the reaction is spontaneous and if ΔG > 0 the reaction is not spontaneous.

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What is Chemistry? What topics are covered in chemistry?

salantis [7]

Answer:

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2 years ago

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According to VSEPR theory, if there are three electron domains in the valence shell of an atom, they will be arranged in a(n) __

wolverine [178]

Answer: B. trigonal planar

Explanation:

Valence Shell Electron Pair Repulsion Theory (VSEPR) is a model to predict the geometry of the atoms making up a molecule where atoms are arranged such that the forces of repulsion are minimum.

If a central atom is bound to three electron domains ,the number of electron pairs is 3, that means the hybridization will be $sp^2$ and the electronic geometry of the molecule will be trigonal planar as the electron pairs will repel each other and attain a position which is most stable.

Example: $BCl_3$ with 3 electron domains has trigonal planar geometry.

6 0

3 years ago

What is the mass of 8.23 x 10^23 atoms of Ag

Gnom [1K]

Answer:

$\boxed {\boxed {\sf Approximately \ 147 \ g\ Ag}}$

Explanation:

Convert Atoms to Moles

The first step is to convert atoms to moles. 1 mole of every substance has the same number of particles: 6.022 ×10²³ or Avogadro's Number. The type of particle can be different, in this case it is atoms of silver. Let's create a ratio using this information.

$\frac{6.022*10^{23} \ atoms \ Ag}{1 \ mol \ Ag}$

We are trying to find the mass of 8.23 ×10²³ silver atoms, so we multiply by that number.

$8.23 *10^{23} \ atoms \ Ag *\frac{6.022*10^{23} \ atoms \ Ag}{1 \ mol \ Ag}$

Flip the ratio so the atoms of silver cancel. The ratio is equivalent, but places the other value with units "atoms Ag" in the denominator.

$8.23 *10^{23} \ atoms \ Ag *\frac{1 \ mol \ Ag}{6.022*10^{23} \ atoms \ Ag}$

$8.23 *10^{23} *\frac{1 \ mol \ Ag}{6.022*10^{23} }$

Condense into one fraction.

$\frac{8.23 *10^{23} }{6.022*10^{23} } \ mol \ Ag$

$1.366655596 \ mol \ Ag$

Convert Moles to Grams

The next step is to convert the moles to grams. This uses the molar mass, which is equivalent to the atomic mass on the Periodic Table, but the units are grams per mole.