Question

A sample of nitrogen (N2) gas in a 10.0L container has a

Answer 1

Answer: The pressure of nitrogen will be 2.0 atm

Explanation:

According to ideal gas equation:

$PV=nRT$

P = pressure of gas = 1.0 atm

V = Volume of gas = 10.0 L

n = number of moles = ?

R = gas constant =$0.0821Latm/Kmol$

T =temperature =$297K$

$n=\frac{PV}{RT}$

$n=\frac{1.0atm\times 10.0L}{0.0820 L atm/K mol\times 297K}=0.41moles$

Now again using ideal gas equation :

$P=\frac{nRT}{V}=\frac{0.41mol\times 0.0821Latm/Kmol\times 297K}{5.0L}=2.0atm$

Thus pressure of nitrogen will be 2.0 atm