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diamong [38]
3 years ago
12

Naturally occurring magnesium exists as three isotopes. 78.70% is Mg-24 with a mass of 23.98504 amu, 10.13% is Mg-25 with a mass

of 24.98584 amu, and 11.17% is Mg-26 with a mass of 25.98259 amu. What is the atomic mass of magnesium?
Chemistry
1 answer:
Nezavi [6.7K]3 years ago
3 0

Answer:

The correct answer is 24.31 amu.

Explanation:

The formula for finding the average atomic mass = The sum of the percentage abundance of isotopes × the actual mass of isotopes

The average atomic mass = % abundance of Mg-24 × actual mass + % abundance of Mg-25 × its actual mass + % abundance of Mg-26 × its actual mass

Avg. Atomic mass = 0.7870 × 23.98504 + 0.1013 × 24.98584 + 0.1117 × 25.98259

Avg. atomic mass = 18.88 + 2.53 + 2.90 = 24.31 amu

The atomic mass of magnesium is 24.31 amu.

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Answer:

a) But-1-ene

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c) Z-But-2-ene

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Explanation:

In this case, if we want to draw the <u>isomers</u>, we have to check the<u> formula </u>C_4_H8 in this formula we can start with a linear structure with 4 carbons. We also know that we have a double bond, so we can put this double bond between carbons 1 and 2 and we will obtain <u>But-1-ene.</u>

<u />

For the next isomer, we can move the double bond to carbons 2 and 3. When we do this can have two structures. When the methyl groups are placed on the same side we will obtain <u>Z-But-2-ene</u>. When the methyls groups are placed on opposite sides we will obtain <u>E-But-2-ene.</u>

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Finally, we can use a linear structure of three carbons with a methyl group in the middle with a double bond, and we will obtain <u>2-Methylpropene.</u>

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See figure 1 to further explanations.

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8 0
3 years ago
Write the balanced COMPLETE ionic equation for the reaction when Na₂CO₃ and AgNO₃ are mixed in aqueous solution. If no reaction
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Answer:

see explanation

Explanation:

Write the balanced COMPLETE ionic equation for the reaction when Na₂CO₃ and AgNO₃ are mixed in aqueous solution. If no reaction occurs, simply write only NR.

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What is the electron configuration of the chlorine atom after it gains an electron?
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Check this question from quizlet :)

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3 years ago
Vinegar is an aqueous solution of acetic acid, ch3cooh. a 5.00 ml sample of a particular vinegar requires 26.90 ml of 0.175 m na
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  The molarity  of  acetic acid in the  vinegar is  0.94 M


 <u><em> calculation</em></u>

Step 1:  write  the balanced equation between CH3COOH  + NaOH

that is CH3COOH   + NaOH  →  CH3COONa  + H2O


step 2 :  find the moles of NaOH

moles  =molarity  x volume in L

volume in liters = 26.90/1000=0.0269 l

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Step 3: use the mole  ratio to find moles of CH3COOH

that is the  mole ratio of  CH3COOH: NaOH is 1:1 therefore  the moles of CH3COOH is  =0.0047  moles


Step 4:  find the  molarity  of  CH3COOH

molarity = moles/volume in liters

volume in liter = 5.00/1000 =0.005 l

molarity  is therefore=0.0047 moles/ 0.005 l = 0.94 M

4 0
4 years ago
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