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3 years ago

The formula to determine energy is uppercase E = one-half m v squared. What is the formula solved for v?

Mathematics

2 answers:

alexandr402 [8]3 years ago

6 0

Answer:

Step-by-step explanation:

$E=\frac{1}{2}mv^2$

All the variables on the right are being multiplied together then the whole mess is being divided by 2. Let's get rid of the 2 first. The undoing of division is multiplication, so we will begin by multiplying both sides by 2 to get

$2E=mv^2$

Next we will move the m. The undoing of multiplication is division. So we divide both sides by m to get

$\frac{2E}{m}=v^2$

The undoing of a square is to take the square root, so we will do that to both sides giving us, finally

$\sqrt{\frac{2E}{m} }=v$

tangare [24]3 years ago

4 0

Answer:

Step-by-step explanation:

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Which of the following is a polynomial with roots: − square root of 5 , square root of 5 , and −3?

tresset_1 [31]

Roots: - √5 , √5, and - 3

=> these are factors of the polynomial: (x + √5), (x - √5), and (x + 3).

Multiply those three factors:

(x + √5) (x - √5) ( x + 3) = [x^2 - 5] ( x + 3 ) = x^2 + 3x^2 - 5x - 15

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3 years ago

What is the y value of the vertex of the function f(x)=-(x-3)(x+11)

AnnyKZ [126]

Answer:

Step-by-step explanation:

Because there is a minus sign infront of x-3, we can convert x-3 into the negative form:

- * x

- * -3

-x + 3

Which gives us:

(-x + 3)(x + 11)

Now expand the brackets with the formula:

(a + b)(c + d) = ac + ad + bc + bd

-x * x = -x²

-x * 11 = -11x

3 * x = 3x

3 * 11 = 33

-x² - 11x + 3x + 33

-x² - 8x + 33

The formula for finding the x coordinate of a vertex in a quadratic equation is:

x = $\frac{-b}{2a}$

Plug known variables in:

$x = \frac{-(-8)}{2(-1)}$

$x = \frac{8}{-2}$

$x = -4$

Now, to find the y coordinate, plug this variable back into the quadratic equation:

-x² - 8x + 33

$y = -(-4^2) - (32) + 33\\y = -16 + 32 + 33\\\\$

y = 49

So the y coordinate of the vertex is 49.

Hope this helps!

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