The graph of which function passes through the point (–3,

Which lines are perpendicular to the line y – 1 = (x+2)? Check all that apply.

yuradex [85]

Answer:

None!

Step-by-step explanation:

Two lines are perpendicular when the product of their slopes equals -1.

The general equation of a line is:

y = m(x-x0) + y0. Where "m" represents the slope and (x0, y0) a point on the line.

Then, we find the slope of each equation:

a) y + 2 = –3(x – 4) -> m=-3

b) y − 5 = 3(x + 11) -> m=3

c) y = -3x -> m= -3

d) y = x – 2 -> m=1

e) 3x + y = 7 -> m= -3

And the slope of the line y – 1 = (x+2) is m=1.

So, multiplying the slopes:

a) -3 * 1 = -3

b) 3 * 1 = 3

c) -3 * 1 = -3

d) 1 * 1 = 1

e) -3 * 1 = -3

None of the lines are perpendicular to the line y – 1 = (x+2)

7 0

3 years ago

I NEED HELP WITH THIS SCIENCE QUESTION!!!

yan [13]

Answer:

69 420

Step-by-step explanation:

3 0

3 years ago

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An engineer designed a valve that will regulate water pressure on an automobile engine. The engineer designed the valve such tha

iren [92.7K]

<h2>Answer with explanation:</h2>

Let $\mu$ be the population mean.

By considering the given information , we have

Null hypothesis : $H_0: \mu=5.85$

Alternative hypothesis : $H_0: \mu>5.85$

Since alternative hypothesis is right-tailed , so the test is a right-tailed test.

Given : n=290 ; $\overline{x}=5.95$ ;

$\sigma=\sqrt{Var}=\sqrt{0.64}=0.8$

Test statistic: $z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

i.e. $z=\dfrac{5.95-5.85}{\dfrac{0.8}{\sqrt{290}}}\approx2.13$

By using the standard normal distribution table for z , we have

P-value for right tailed test : $P(Z>z)=1-P(Z$

$=1-P(z$

Since , the P-value is greater than the significance level of $\alpha=0.01$ , it means we do not have evidence to reject the null hypothesis.

Hence, we conclude that we do not have enough evidence to support the claim that valve performs above the specifications.

7 0

3 years ago

Please help me idk what this is

-Dominant- [34]

2 12/30
16/40
-4/20

LOL that ixl.com grind

6 0

3 years ago

Read 2 more answers

Did the population of Town C increase by at least 100 percent from the year 2000 to the year 2010 ? The population of Town C in

mart [117]

Yes, the population of Town C increased by at least 100 percent from the year 2000 to the year 2010

<u>Statement 1:</u> The population of Town C in 2000 was 2/3 of the population in 2005

This tells us the population change from 2000 to 2005 since we need to know the population change from 2000 to 2010, this statement is not sufficient.

<u>Statement 2: </u>The population of Town C increased by a greater number of people from 2005 to 2010 than it did from 2000 to 2005.

Since statement 2 provides no information about the population change from 2000 to 2005, there is no to answer this question with certainty. thus, statement 2 is not sufficient

<u>Statement 1 and Statement 2 combined:</u>

Let X= the population in 2000

Let Y= the population in 2005

Let Z= the population in 2010

From statement 1, we can write: X= $\frac{2}{3}$ Y