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nordsb [41]
3 years ago
15

Halp me plz now I need to go to school Now

Mathematics
1 answer:
ANEK [815]3 years ago
3 0
11.) All you've got to do is subtract thirty-eight(38) from eighty-one(81). This will result in 43.

81-38=43

12.) You've got to subtract eighty-seven(87) from ninety(90) which will give you the answer 3.

87-90=3
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Cam was bom weighing 8.6 pounds. Every day, he gained the same amount of weight. After 30 days, he weighed 14.9
guajiro [1.7K]

Answer:

So I'm not entirely sure about this one, but I believe he gained 0.21 pounds each day for 30 days

Step-by-step explanation:

Since Cam was born weighing 8.6 pounds and after 30 days weighed 14.9, subtract 14.9-8.6 to find how much he gained.

14.9 - 8.6 = 6.3

Now that we know how much he gained, we have to find out how much he gained per day for 30 days. To do this, divide 6.3 by 30

6.3 / 30 = 0.21

To make sure this answer is correct, multiply 0.21 by 30 and add that to 8.6. It should equal 14.9.

I hope this helps!

7 0
2 years ago
Read 2 more answers
What is the value of k in the equation 5k-2k=12
Mamont248 [21]

Answer:

k =4

Step-by-step explanation:

5k-2k=12

Combine like terms

3k = 12

Divide each side by 3

3k/3 = 12/3

k = 4

5 0
3 years ago
Read 2 more answers
Danielle worked at the warehouse after school. She earned $9.25 per
Elza [17]
Huh? I honestly am lost in this world it’s draining my mental health....what if I just end it? Will anyone care? Probably not....... I’m not allowed to feel this way bc my parents say it’s the devil trying to take me away from god but honestly I don’t believe that..
6 0
2 years ago
Please help ASAP.. I don’t understand.
Dmitry_Shevchenko [17]

Y intercept means x = 0, on x= 0 y is also zero so the cordinate is (0,0)

8 0
3 years ago
Solving Exponential and Logarithmic Equation In exercise,solve for x or t.See example 5 and 6.
Aloiza [94]

Answer:

0.70275

Step-by-step explanation:

Data provided in the question:

4e²ˣ⁻¹ -1 = 5

now solving for 'x'

⇒ 4e²ˣ⁻¹ = 5 + 1

or

⇒ 4e²ˣ⁻¹ = 6

or

⇒ e^{(2x-1)} =\frac{6}{4}

or

⇒ e^{(2x-1)} =\frac{3}{2}

now,

taking natural log both sides, we get

⇒ 2x - 1 = \ln(\frac{3}{2})

also,

we know

⇒ \log(\frac{A}{B}) = \log(A)+\log(B)

thus,

⇒ 2x - 1 = ln(3) - ln(2)

or

⇒ 2x - 1 = 1.0986 - 0.6931

or

⇒ 2x - 1 = 0.4055

or

⇒ 2x = 0.4055 + 1

or

⇒ 2x = 1.4055

or

⇒ x = 0.70275

3 0
3 years ago
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