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3 years ago

7

A collector is selling antique coins from a collection. Currently, each coin is worth $11.50. the value of each coin is expected

to increase by $1.35 per month. If Jennifer purchases 25 coins, what is the expected value of the coins 12 months from now?

1 answer:

Phoenix [80]3 years ago

4 0

The answer to your question is 4657.50

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Write the first five terms of the arithmetic sequence. First term: -8 and common difference: -2

Hunter-Best [27]

Answer:

-8,-10,-12,-14,-16

Step-by-step explanation:

Just take -8 and add -2 to find each term

7 0

3 years ago

The following data gives the speeds (in mph), as measured by radar, of 10 cars traveling north on I-15. 76 72 80 68 76 74 71 78

____ [38]

Answer:

71.123 mph ≤ μ ≤ 77.277 mph

Step-by-step explanation:

Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:

$m-t_{a/2,n-1}\frac{s}{\sqrt{n} }$ ≤ μ ≤ $m+t_{a/2,n-1}\frac{s}{\sqrt{n} }$

Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and $t_{a/2,n-1}$ is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.

the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.

So, if we replace m by 74.2, s by 5.3083, n by 10 and $t_{0.05,9}$ by 1.8331, we get that the 90% confidence interval for the mean speed is:

$74.2-(1.8331)\frac{5.3083}{\sqrt{10} }$ ≤ μ ≤ $74.2+(1.8331)\frac{5.3083}{\sqrt{10} }$

74.2 - 3.077 ≤ μ ≤ 74.2 + 3.077

71.123 ≤ μ ≤ 77.277

8 0

3 years ago

1. The following set of numbers is going to be graphed on a histogram.

statuscvo [17]

Answer:

i have the same question pls help us

Step-by-step explanation:

4 0

2 years ago

A pebble falls of a cliff at a height of 256 ft. If the equation for the height as a function is h(t)=-16^2 + initial height whe

AlladinOne [14]

Answer:

After 4secs

Step-by-step explanation:

Given the function of the height expressed as;

h(t)=-16^2 + initial height

If initial height = 256, then;

h(t) = -16t^2 + 256t

The pebble will hot the ground at when h(t) = 0

Substitute

0 = -16t^2 + 256t

16t^2 = 256

t^2 = 256/16

t^2 = 16

t = 4

Hence the pebble will hit the ground after 4secs

6 0

2 years ago

Which are the solutions of the quadratic equation? x^2 = –5x – 3

ollegr [7]

<span>x=<span><span><span>−5</span>2</span>+<span><span><span><span>12</span><span>√13</span></span><span> or </span></span>x</span></span></span>=<span><span><span>−5</span>2</span>+<span><span><span>−1</span>2</span><span>√<span>13</span></span></span></span>

3 0

3 years ago