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Nutka1998 [239]
3 years ago
6

In a survey, 250 out of 1000 people said that they preferred a particular brand of shampoo. What is the result of the survey in

percent?
Mathematics
2 answers:
ipn [44]3 years ago
8 0

25% said that they preferred a particular brand of shampoo, the rest is 75 %

ANTONII [103]3 years ago
6 0

25% because you divide the numerator and denominator by 10.

25% for one and 75% for the other.

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Write an expression with a value of 12.it should contain four numbers and two different operations
sergey [27]
Roughly what I gave your doppelganger (you + 1) a few minutes ago . . .

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4 0
3 years ago
Here is a list of numbers:<br> 2, 13, 13, 6, 10,4 16,14,20<br> State the median.
Travka [436]

Answer:

Median = 13

Step-by-step explanation:

Arranging it in ascending order:

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Median is the middlemost no.

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=> Median = 13

5 0
3 years ago
Read 2 more answers
What percent of 200 is 230
coldgirl [10]
The percent is 115% if put the numbers into a fraction know when finding a percent you can make the numbers you have already into a fraction so the fraction you have is 230/200 because 200 IS 230 so the number that IS is on top of the infraction  so it 230/200=x/100. there is a x because you don't know what the percent is ,also the total percent you can get is a 100% so the x on top of a hundred so you do cross multiplying so 230 times 100 divided by 200 equals 115
4 0
3 years ago
Simplify the inequality obtained in part iii.
Trava [24]

<em>You've simplified it as much as possible.</em>

<em>Let x equal length of flight in hours.</em>

<em>At first, the inequality was:</em>

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4 0
3 years ago
It is known that 60% of customers will need additional maintenance on their vehicle when coming in for an oil change. A random s
inn [45]

Answer:

the probability that more than 70% of customers in the sample will need additional maintenance is 0.0371

Step-by-step explanation:

From the information given:

we are to determine the probability that more than 70% of customers in the sample will need additional maintenance

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Then X \sim Bin(48, 0.6)

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= P(X> 34)

= \sum \limits ^{48}_{x=34} (^{48}_{x}) (0.6)^x(1 - 0.6)^{48-x}

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= 0.03709524328

\simeq 0.0371

3 0
3 years ago
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