Answer:
I will need 26.4 pounds of the expensive nuts and 1.6 pounds of the cheap nuts.
Step-by-step explanation:
Since I have one type of nut that sells for $ 4.50 / lb and another type of nut that sells for $ 8.00 / lb, and I would like to have 28 lbs of a nut mixture that sells for $ 7.80 / lb, to determine how much of each nut will I need to obtain the desired mixture, the following calculation must be performed:
8 x 0.95 + 4.5 x 0.05 = 7.825
8 x 0.94 + 4.5 x 0.06 = 7.79
0.94 x 28 = 26.32
26.4 x 8 + 1.6 x 4.5 = 218.4
218.4 / 28 = 7.8
Thus, I will need 26.4 pounds of the expensive nuts and 1.6 pounds of the cheap nuts.
Answer:
x = 0, y = 2
Step-by-step explanation:
- solve the equation for x
3x + 3(x + 2) = 6
2. Substitute the given value of x into the simplest equation y= x + 2
y = 0 + 2
3. Solve the equation for y
y= 2
4. The possible solution of the system is the ordered pair ( x, y)
( x, y) = ( 0, 2)
Answer:
Step-by-step explanation:
−7−4p+5
−4p+(−7+5)
Ans
−4p−2
-1 1/2 is the answer. I'm making 20 characters.
