Answer:
In words the answer is between t=0 and t=2.
In interval notation the answer is (0,2)
In inequality notation the answer is 0<t<2
Big note: You should make sure the function I use what you meant.
Step-by-step explanation:
I hope the function is h(t)=-16t^2+32t because that is how I'm going to interpret it.
So if we can find when the ball is on the ground or has hit the ground (this is when h=0) then we can find when it is in the air which is between those 2 numbers.
0=-16t^2+32t
0=-16t(t-2)
So at t=0 and t=2
So the ball is in the air between t=0 and t=2
Interval notation (0,2)
Inequality notation 0<t<2
Answer:
78.55m^2
Step-by-step explanation:
General formula for the area of a circle is πr^2
π=3.12
r=5m
So let's apply the formula
3.142×(5)^2
3.142×25
78.55
So the area is 78.55m^2
The required measures of the angle are given as,
∠JKL = 72° ∠MLK = 108° ∠JMK = 36°
∠MJL = 54° ∠KNL = 90°
Given that.
The measure of the rhombus is given, we have to determine the measure of the angles,
<h3>What is angle?</h3>
orientation of one line with respect to the horizontal or other respective line is known as a measure of orientation and this measure is known as angle.
Here,
∠JKL= 2 × ∠JKM = 72°
∠MLK = 180 - 2 × ∠JKM = 108°
∠JMK = ∠JKM = 36°
∠MJL = ∠MLK/2 = 54°
The diagonal of the rhombus bisect each other at an angle of 90°
So,
∠KNL = 90°
Thus, all the measure of the angles is shown above.
Learn more about Angles here:
brainly.com/question/13954458
#SPJ1
I think there is only one 0. If x=2, then 3 does not equal 0.
