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DanielleElmas [232]
3 years ago
15

Does the number 15/3 belong to the set of natural/counting numbers?

Mathematics
1 answer:
madreJ [45]3 years ago
5 0
No 15/3 does not belong to the set of numbers
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Joey wrote a book about his favorite Author.
Rasek [7]

Answer: $6000

Step-by-step explanation:

Multiply the cost of the book by the decimal equivalent of 12% (25 x .12).  this equal 3 dollars per book.  2,000 copies of the book were sold, so you would multiply 2000 by 3.  2000 x 3 = 6000

7 0
3 years ago
If and , find .<br><br> A. <br> B. <br> C. <br> D.
trapecia [35]
Answer: option D. 2x^2 + (3/2)x  - 5

Explanation:

1) polynomials given:

 f(x) = x/2 - 2 and g(x) = 2x^2 + x - 3

2) question: find (f + g) (x)

That means that f(x) + g(x), so you have to add up the two polynomials given.

3) x/2  - 2 + 2x^2 + x - 3

4) Combine like terms:

a) terms with x^2: you only have 2x^2, so it is not combined with other term.

b) terms with x: x/2 + x

that is a sum of fractions: x/2 + x = [x + 2x] / 2 = 3x / 2 = (3/2)x

c) constant terms: - 2 + (-3) = - 2 - 3 = - 5

5) Result: 2x^2 + (3/2)x - 5

That is the option d.


4 0
3 years ago
The absolute value of 4 + 7i is equal to the square<br> root of<br> DONE
leva [86]

Answer:

radical 65

Step-by-step explanation:

4+7 are squred and under a radical bar

4^2 +7^2= 16 +49 under radical bar

radical 16+49=radical 65

good luck

8 0
2 years ago
How to figure out median weight
statuscvo [17]
They need look a median wieght.
7 0
3 years ago
1. Among 806 people asked which is there favorite seat on a plane, 492 chose the window seat, 8 chose the middle seat, and 306 c
prisoha [69]

Answer:

See explanation

Step-by-step explanation:

Among 806 people asked which is there favorite seat on a plane, 492 chose the window seat, 8 chose the middle seat, and 306 chose the aisle seat, then

P(\text{Window seat})=\dfrac{492}{806}=\dfrac{246}{403}\\ \\P(\text{Middle seat})=\dfrac{8}{806}=\dfrac{4}{403}\\ \\P(\text{Aisle seat})=\dfrac{306}{806}=\dfrac{153}{403}

a) One randomly selected person preferes aisle seat with probability

\dfrac{153}{403}

b) Two randomly selected people both prefer aisle seat (with replacement) is

\dfrac{306}{806}\cdot \dfrac{306}{806}=\dfrac{153}{403}\cdot \dfrac{153}{403}=\dfrac{23,409}{162,409}

c) Two randomly selected people both prefer aisle seat (without replacement) is

\dfrac{306}{806}\cdot \dfrac{305}{805}=\dfrac{153}{403}\cdot \dfrac{61}{161}=\dfrac{9,333}{64,883}

8 0
2 years ago
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