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Elena-2011 [213]
3 years ago
12

What is the slope? Please Help

Mathematics
2 answers:
Triss [41]3 years ago
6 0

Answer:

-1

Step-by-step explanation:

Pick two points on the line

(0,2) and (2,0)

Using the slope formula

m = ( y2-y1)/(x2-x1)

    = ( 0-2)/(2-0)

    = -2/2

  = -1

gizmo_the_mogwai [7]3 years ago
5 0

Answer:

-1

Step-by-step explanation:

Use two points on the line to find the slope, using rise over run.

We can use the points (0, 2) and (2, 0).

From the first point to the other, the y value decreases by 2 and the x value increases by 2.

Use rise (change in y value) over run (change in x value):

-2 / 2

= -1

So, the slope is -1.

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HELP ASAP ITS TIMED
Natasha_Volkova [10]

Answer:

  x + 10 = x² + 1

(third option listed)

Step-by-step explanation:

assuming that you meant: \sqrt{x+10-1}=x  , because otherwise there would be no equivalent relationships,

(goal: isolate x on one side of the equation whilst having x on the other side of the equation also, like the equation in the question)*

   x + 10 = x² + 1

        -1            -1

   x + 10 - 1 = x²

  \sqrt{x+10-1} =\sqrt{x^2}                  [find √ of both sides to isolate x]

\sqrt{x+10-1} =x         (equation in problem)

       

{note: there's no reason to not simplify the equation to \sqrt{x+ 9, but the question leaves the equation that way, so I didn't simplify it either}

*I used this goal to decide which equations seemed about right, and then trying to test things out in my head

3 0
2 years ago
Read 2 more answers
Need help on #25 please!! Show your work
hjlf
10 : 90; 10÷10= 1; 90÷10= 9; 1:9 or 1/9
Hope this helps
6 0
3 years ago
Read 2 more answers
An Elevator descends into a mine shaft at the rate of 5m/min. If the descend starts from 15m above the ground, how long will it
zhenek [66]
First of all, assuming that the "ground level" is 0; 

The lift is not starting from 0, so we also need to account for the extra 15 meters above the ground the lift is. 

The total distance the lift would cover in the downward direction: 15+350=365m

Now, you know that the lift covers 5 m/min

Therefore, 5x=365 (ignoring units because they can complicate things) 

x=365/5 
x=73 minutes 

Therefore, they would take 73 minutes to reach 350 m deep into the ground with a starting position 15 m above the ground. 

Hope I helped :) 
5 0
3 years ago
Help?????????????????
seraphim [82]

Answer:

yes it does

Step-by-step explanation:

as you can see,

in a function, we don't have more than one y for a x, so here we have one y for each x. then it is

7 0
3 years ago
Suppose lines EF and GH are reflected over the line Y equals X to form the lines JK and LM which statement would be true about t
katrin [286]

Answer:

A) JK and LM will be parallel to each other.

Step-by-step explanation:

On reflection on y=x line the x co-ordinate changes with y co-ordinate and y co-ordinate changes with x co-ordinate

(x,y)\rightarrow (y,x)

Points on line EF

(0,6) , (-5,-2)

On reflection of this line on y=x the new points we get for line JK are

(6,0),(-2,-5)

Points on line GH

(-4,9),(-9,1)

On reflection on y=x line the new points we get for line LM are

(9,-4),(1,-9)

Slope of line JK

m=\frac{y_2-y_1}{x2-x1}\\m=\frac{(-5)-0}{(-2)-6} \\m=\frac{-5}{-8}=\frac{5}{8}

Slope of line LM

m=\frac{y_2-y_1}{x2-x1}\\m=\frac{(-9)-(-4)}{1-9} \\m=\frac{-9+4}{-8}=\frac{-5}{-8}\\m=\frac{5}{8}

For two line to be parallel, their slopes will be same.

m_{JK} =\frac{5}{8} , m_{LM}=\frac{5}{8}

Since slopes of lines JK and LM are same therefore we can say that these are parallel to each other.

5 0
3 years ago
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