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stepan [7]
3 years ago
14

Charlie’s pizza charges $12 for a medium cheese pizza plus $2 for each additional topping. The cost of a medium pizza, y, with x

toppings is represented by this equation:
y = 12 + 2x

Which graph represents this equation?

Mathematics
1 answer:
brilliants [131]3 years ago
4 0

Answer:

<u>The correct answer is Graph A. It's the only graph with the right values for (x, y) within the Cartesian plane. </u>

Step-by-step explanation:

1. Let's review the data given to us for solving the question:

Amount that Charlie’s pizza charges for a medium cheese pizza = US$ 12

Amount that Charlie’s pizza charges for each additional topping = US$ 2

Cost of a medium pizza (y) with (x) toppings is represented by the equation:

y = 12 + 2x

2. Let's find the values for the equation:

When no toppings are added:

y = 12 + 2 * 0 = 12 + 0 = 12

When 1 topping is added:

y = 12 + 2 * 1 = 12 + 2 = 14

When 2 toppings are added:

y = 12 + 2 * 2 = 12 + 4 = 16

When 3 toppings are added:

y = 12 + 2 * 3 = 12 + 6 = 18

When 4 toppings are added:

y = 12 + 2 * 4 = 12 + 8 = 20

As we can see, the graph starts with the point (0, 12) and continues with (1, 14), (2, 16), (3, 18), (4, 20).  

Graph B starts with the point (0, 4) and graph C with the point (0,6). They're incorrect. And graph D starts with (0, 12) but continues with (1, 13), (2, 14) (3, 15) and (4, 16), so this graph is also incorrect.

<u>The only graph with the right values for the Cartesian plane is Graph A.</u>

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Answer:

111.65

Step-by-step explanation:

$15.25 x 3 = $45.75

$32.95 x 2 = $65.9

Total: $111.65

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2 years ago
On the 1st January 2014 Carol invested some money in a bank account.
Ghella [55]

Answer:

\large \boxed{\text{\pounds 23 360.00}}

Step-by-step explanation:

The formula for the accrued amount from compound interest is

A = P \left(1 + \dfrac{r}{n}\right)^{nt}

1. Amount in account on 1 Jan 2015

(a) Data:

a = £23 517.60

r = 2.5 %

n = 1

t = 1 yr

(b) Calculations:  

r = 0.025

\begin{array}{rcl}23517.60 & = & P\left (1 + \dfrac{r}{n}\right)^{nt}\\\\& = & P\left (1 + \dfrac{0.025}{1}\right)^{1\times1}\\\\& = & P (1 + 0.025)\\ & = & 1.025 P\\P & = & \dfrac{23517.60 }{1.025} \\\\& = & 22 944.00 \\\end{array}

The amount that gathered interest was £22 944.00 but, before the interest started accruing, Carol had withdrawn £1000 from the account.

She must have had £23 944 in her account on 1 Jan 2015.

(2) Amount originally invested

(a) Data

A = £23 944.00

\begin{array}{rcl}23 944.00 & = & 1.025 P\\P & = & \dfrac{23 944.00 }{1.025} \\\\& = & \mathbf{23 360.00} \\\end{array}\\\text{Carol originally invested $\large \boxed{\textbf{\pounds23 360.00}}$ in her account.}

3. Summary

1 Jan 2014      P = £23 360.00

1 Jan 2015     A =    23 944.00

     Withdrawal = <u>    -1  000.00 </u>

                     P =     22 944.00

1 Jan 2016    A =    £23 517.60

5 0
3 years ago
Anwser these questions
Sveta_85 [38]
Use photo math , it helps lol
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2 years ago
Please help me out with this!
olganol [36]
A. y-intercept

B. The slope is 3/4, the y-intercept is 0

C. For this one you need to put it in y-intercept form. So, you subtract 2x, and move it over to 12. The equation would look like 6y = 2x + 12.

Then, divide everything by 6, and the equation would look like: y = 2/6x + 2

Thus, the slope is 2/6x and 2 is the y-intercept.
3 0
3 years ago
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