second compound
Let molar mass of x is = X
Let molar mass of y is = Y
Moles of x in second compound = Mass / molar mass = 7 / X
Moles of y in second compound = Mass / molar mass = 4.5 / Y
For second compound
7 / X : 4.5/ Y = 1:1
Therefore
X / Y = 7/4.5
Y / X = 4.5/ 7
The mass of x in first compound = 14g
moles of x in first compound = 14/X
Mass of y in first compound = 3
moles of y in first compound = 3 / Y
14 / X : 3/ Y = 14Y / 3X = 14 X 4.5 / 3 X 7 = 3 :1
Thus molar ratio in first compound = moles of x / Moles of y = 3:2
Formula = x3y
Answer : The length of a one-dimensional box for an electron is 
Explanation :
The energy level of quantum particle in a one-dimensional box is given as:
where,
= 479 kJ/mol = 479000 J/mol
n = energy level = 1
h = Planck's constant = 
m = mass of electron = 
L = length of a one-dimensional box = ?
Now put all the given values in the above formula, we get:
conversion used : 
Therefore, the length of a one-dimensional box for an electron is
Answer:
15.5 km
Explanation:
1.55 x 10^4 m means 1.55 x 10000 = 15,500 m
1 km = 1000 meters
To convert to km we divide by 1000
So 15,500/1000
= 15.5 km
To compute the percent error, you divide the absolute difference between the actual value and the measured value with the actual value. Then, multiply it with 100 to get the percentage. The solution is as follows:
Percent error = (250 - 243.9)/250 * 100
Percent error = 2.44%
